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3 years ago

If the bond enthalpy for a C-H bond is 413 kJ, what will happen when the C-H bond is broken?

Physics

1 answer:

pentagon [3]3 years ago

8 0

Explanation:

Bond Enthalpy : It is defined as amount of energy required to break a the particular bond in there gaseous state. It is also known as bond energy. It units are kJ/mol.

Breaking of a bond is an Endothermic process (energy absorbed from the surroundings).

Formation of bond is an Exothermic process (energy is released to the surroundings).

If the average bond enthalpy for a C-H bond is 413 kJ/mol, When the C-H bond breaks in which energy will be required ,which will be an endothermic reaction.

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Yes but then you need to find out what will happen then try the other wire

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4 years ago

The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act

marta [7]

Answer:

Explanation:

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4 years ago

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A baseball player uses a bat to hit a 0.145-kilogram stationary baseball with a force of 18,436 newtons. What is the force, in n

Anna35 [415]

Answer:

18,436 newtons

Explanation:

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2 years ago

A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex

Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

$v_i = v_o$

now at the end of 80 s let the speed is

$v_f = v_1$

after another 120 s let the speed will be

$v_f' = v_2$

now we know that

$d = \frac{v_i + v_f}{2} (t)$

$d = \frac{v_o + v_1}{2}(80)$

$1000 = 40(v_o + v_1)$

also we know that

$v_1 - v_o = a(80)$

also we have

$1000 = \frac{v_1 + v_2}{2}(120)$

$1000 = 60(v_1 + v_2)$

now we can say

$(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}$

also we know

$v_2 - v_o = a(120 + 80)$

$-8.33 = 200 a$

$a = -0.042 m/s^2$

Part b)

now we have

$v_1 + v_o = 25$

$v_1 - v_o = (-0.042)(80)$

$v_1 = 10.83 m/s$

so the starting velocity of the trip is

$v_o = 25 - 10.83 = 14.17 m/s$

now speed after t = 200 s is given as

$v_2 = v_o + at$

$v_2 = 14.17 - (0.042)(200)$

$v_2 = 5.77 m/s$

5 0

3 years ago

A ship can carry more load than aeroplane of same size. why?

stepladder [879]

Answer:

density of water is much greater than density of air

Explanation:

when body is in fluid it carries weight which is always equal to upthrust

upthrust is given as

upthrust= density of fluid ×strength of gravitational field g × volume of body in fluid

as volume of ship and aeroplane is same and strength of gravitational field or acceleration due to gravity is same hence upthrust depens upon density of fluid .

density of air is about 1.2 kg/m^3 and density of water is 1000kg/m^3 hence ship carries more load

8 0

4 years ago