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Alecsey [184]
3 years ago
5

Which of the following is true about a planet orbiting a star in the uniform circular motion? B. The speed of the plant is alway

s changing. C. The velocity of the plant is constant. D. The acceleration vector of the plant points towards the center of the circle.

Physics
1 answer:
ivanzaharov [21]3 years ago
5 0

Explanation:

  • If an object moves in a circular path, this type of motion is called uniform circular motion.
  • The speed of the object is constant in this type of motion.
  • As velocity is a vector quantity, it keeps on changing. It can be given by drawing tangent to the circle.
  • Acceleration acts towards the center of circle.
  • Hence, out of the given four options, the correct statement about a planet orbiting a star in uniform circular motion is (d) i.e. The acceleration vector of the plant points towards the center of the circle.
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A jet airliner moving initially at 612 mph (with respect to the ground) to the east moves into a region where the wind is blowin
Ganezh [65]

Answer:

966.22 mph

Explanation:

Velocity of plane with respect to wind (Vp,w)= 612 mph east

velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of

east

Write the velocities in vector form

V_{p,w}=612\widehat{i}

V_{w,g}=362\left ( Cos15\widehat{i}+Sin15\widehat{j} \right )= 349.67\widehat{i}+93.69\widehat{j}

Use the formula for the relative velocity

V_{p,w}=V_{p,g}-V_{w,g}

Where, V(p,w) is the velocity of plane with respect to wind

V(p,g) is the velocity of plane with respect to ground

V(w,g) is the velocity of wind with respect to ground

So, V_{p,g}=V_{p,w}+V_{w,g}

V_{p,g}=\left ( 612+349.67 \right )\widehat{i}+93.69\widehat{j}

V_{p,g}=961.67\widehat{i}+93.69\widehat{j}

Magnitude of velocity of lane with respect to ground

V_{p,g} = \sqrt{961.67^{2}+93.69^{2}}

V(p,g) = 966.22 mph

5 0
4 years ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
Andrej [43]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

6 0
3 years ago
Help fast plsss ! which statement is true for nuclear reactions but not for chemical reactions?
padilas [110]

Answer:

B

Explanation: a chemical reaction is only the rearrangement of electrons where a nuclear reaction actually changes the elements and thus the nuclei

5 0
3 years ago
Helpppppppppppp.......!
Black_prince [1.1K]

Explanation:

m = 66 kg

a = 2 m/s²

F = .....?

<h3>F = m . a</h3>

= 66 . 2

= 132 N

<h3>#CMIIW</h3>

3 0
3 years ago
PUBLIC SCHOOLS
padilas [110]

Answer:

D. The cart is moving at a constant speed or velocity

Explanation:

Equilibrium is a state of body in which it is either at rest or moves with uniform velocity. The sum of forces acting on such a body is always zero and the sum of all the torques acting on it is also zero.

There are two types of equilibrium as follows:

Static Equilibrium: When a body is at rest it is said to be in static equilibrium.

Dynamic Equilibrium: When a body is moving with constant velocity, then it is said to be in dynamic equilibrium.

Hence, the correct option here will be:

<u>D. The cart is moving at a constant speed or velocity</u>

4 0
3 years ago
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