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Paul [167]
2 years ago
8

What is the acceleration of a 100 kg object pushed by Beau with a force of 500 N? Write out your equation.

Physics
1 answer:
Aneli [31]2 years ago
4 0

Answer:

ProvideD :

  • Mass ( m ) = 100 kg , Force ( F ) = 500 N

To FinD :

  • Acceleration ( a )

SolutioN :

  • We know , F = ma so put up the values and then solve for a

\longrightarrow \tt \: 500 = 100a

\longrightarrow \tt \:  \frac{500}{100}  = a

\longrightarrow  \tt \: a =  \: \boxed { \tt{5 \: ms ^{ - 2}  }}

  • The acceleration produced is 5 ms ^ -2 .

--------------- HappY LearninG <3 --------------

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7 0
3 years ago
Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
pishuonlain [190]
Hey there!

a \ student  \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only  \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\   \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer!

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7 0
3 years ago
A 200g air-track glider is attached to a spring. The glider is pushed in 10cm and released. A student with a stopwatch finds tha
cricket20 [7]

The spring constant will be k= 5.5N/m for a 200g air track glider attached to a spring.

<h3>What is spring constant?</h3>

The spring constant, k, is a measure of the stiffness of the spring. It is different for different springs and materials.

Calculation for What is the spring constant

First step is to calculate the time period

T = 12 second/10

T = 1.2 second

Now let calculate the spring constant using this formula

k=\dfrac{4\pi ^2m}{T^2}

Where,

m=0.2kg

T=1.2second

k represent spring constant=?

Let plug in the formula

k=\dfrac{4 \pi \times 0.2}{(1.2)^2}

k=\dfrac{39.48\times 0.2}{1.44}

k=\dfrac{7.90}{1.44}

k=5.48 N/m

k=5.5 N/m ( Approximately)

Therefore the spring constant will be 5.5 N/m

To know more about spring constant follow

brainly.com/question/1968517

#SPJ4

4 0
2 years ago
O((&gt;ω&lt; ))oo((&gt;ω&lt; ))oo((&gt;ω&lt; ))oo((&gt;ω&lt; ))oo((&gt;ω&lt; ))o
Paladinen [302]

Answer:

(•_•)

Explanation:

7 0
3 years ago
In case of collision of objects in two dimensions which statement is true after the collision?
Grace [21]

The correct answer to the question is : C) The horizontal momentum and the vertical momentum are both conserved. 

EXPLANATION :

Before coming into any conclusion, first we have to understand the law of conservation of momentum.

As per the law of conservation of momentum, the total linear as well as angular momentum of an isolated system is always conserved . The law of conservation of energy is a universal fact.

Hence, during any type of collision, the total momentum is always conserved.

Hence, the total horizontal momentum as well as total vertical momentum are always conserved during both elastic as well as inelastic collision.



5 0
3 years ago
Read 2 more answers
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