The refrigerator's coefficient of performance is 6.
The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.
As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.
The heat produced in the cold compartment, H = 780.0 J
Work done in ideal refrigerator, W = 130.0 J
Refrigerator's coefficient of performance = H/W
= 780/130
= 6
Therefore, the refrigerator's coefficient of performance is 6.
Energy conservation requires the exhaust heat to be = 780 + 130
= 910 J
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Answer:
8 m/s²
Explanation:
Given,
Force ( F ) = 4 N
Mass ( m ) = 0.5 kg
To find : -
Acceleration ( a ) = ?
Formula : -
F = ma
a = F / m
= 4 / 0.5
= 40 / 5
a = 8 m/s²
It's acceleration is 8 m/s².
Answer:
58515.9 m/s
Explanation:
We are given that



We have to find the speed (vf).
Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.





Using the formula


Where mass of sun=


(B) The balloon will rise because the upward buoyant force is greater than its weight.
Explanation:
In order to evaluate what happens to the balloon, we need to compare the magnitude of the two forces acting on the balloon:
- Its weight, W, acting downward
- The buoyant force, B, acting upward
The weight of the balloon is given by:

where
m = 2.0 kg is the mass of the balloon
is the acceleration of gravity
Substituting,

The buoyant force on the balloon is given by:

where
is the air density
is the balloon's volume
is the acceleration of gravity
Substituting,

We observe that the buoyant force B is larger than the weight, so the balloon will accelerate upward, and the correct answer is
(B) The balloon will rise because the upward buoyant force is greater than its weight.
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