Answer:
the magnitude of the magnetic force on the wire is 0.2298 N
Explanation:
Given the data in the question;
we know that, the magnitude of magnetic force is given as;
|F
| = I(
× 
)
given that
I = 2.6 A
= 0.17
= 0.52
so we substitute
|F | = 2.6( 0.17i" × 0.52j" )
|F | = 0.2298 N
Therefore, the magnitude of the magnetic force on the wire is 0.2298 N
Answer:
From the narrative in the question, there seem to have been a break failure and the ordered step of response to this problem is to
1) Put on the hazard light to inform other road users of a problem or potential fault with your car and so they should continue their journey with caution.
2) Avoid pressing on the acceleration pedal as this might cause the car to gradually slow down due to friction and gravity
3)Try navigate the car to the service lane. This is the less busy lane where cars are sometimes parked briefly.
4) Continuously pump the breaks to try stop the car. Continuously pumping the breaks might just help you build enough pressure to stop the car because often time, there are some pressure left in the break.
5) At this point, the speed of the car should be relatively slow. So at this point, you could try apply the emergency hand break. Do not pull the emergency hand breaks if the car is on high speed. Doing this may cause the car to skid off the road.
Answer:
not sure. I'll try answering this later
Explanation:
I'm not sure. I'll try answering this later .
Answer:
mass goes down volume remains the same
Answer:
at t = 0.001 we have
at t = 0.01
at t = infinity
Explanation:
As we know that they are in series so the voltage across all three will be sum of all individual voltages
so it is given as
now we will have
now we have
So we will have
at t = 0 we have
q = 0
also we know that
at t = 0 i = 0
so we have
at t = 0.001 we have
at t = 0.01
at t = infinity
