I think, either 100 degrees celsius (as of water)
56 degrees celsius (acid)
or 118.1 degrees celsius (acetone)
This the balanced equation based on the question
.
We then proceed with the following calculations
The answer is 
is produced.
Na(s) forms an ionic bond.
<h3>What is ionic bond?</h3>
The main interaction in ionic compounds is ionic bonding, a type of chemical bonding that involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities. Along with metallic and covalent bonds, it is one of the most common types of bonds. Atoms (or collections of atoms) possessing an electrical charge are known as ions. Ions with negative charges are created when atoms gain electrons (called anions). Positively charged ions are produced when atoms lose electrons (called cations). In contrast to covalence, this electron transfer is referred to as electrovalence.
Ionic chemicals normally do not conduct electricity when solid, only when molten or in solution. Depending on the charge of the ions they are made of, ionic compounds typically have a high melting point.
To learn more about ionic bond from the given link:
brainly.com/question/13526463
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Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g
Answer:
If a metal and metal solution react, the more reactive metal will displace the less reactive metal from solution. If the metal in solution you start with is formed from a more reactive metal than the metal to be added, no reaction will occur.
