The ideal gas law may be written as
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)
For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol
Therefore
Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
= 221.95 kPa
= (2.295 x 10⁵)/101325 atm
= 2.19 atm
Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)
Answer: The body produce NADPH a reducing equivalents as antioxidants.
Explanation:
During the pentose phosphate pathway reducing equivalents like NADPH is produced which help to prevent oxidative stress. It reduces glutathione via glutathione reductase which converts reactive H2O2 to H2O by glutathione peroxidase.
Explanation:
Molar mass of HBr = 81 g/mol
Molar mass of nitrogen dioxide gas = 46 g/mol
Molar mass of ethane = 30 g/mol
Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.
The formula for average kinetic energy is:
where,
k = Boltzmann’s constant = 
T = temperature = 273.15 K ( at STP)
As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.
So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.
Because they are not on the periodic tsble they are on the back and they goes together
Answer:
18.33 ×10²³ atoms
Explanation:
Given data:
Molar mass of sulfuric acid = 98.1 g/mol
Mass of sulfuric acid = 75.0 g
Number of of oxygen atom present = ?
Solution:
Number of moles of sulfuric acid:
Number of moles = mass/molar mass
Number of moles = 75.0 g/ 98.1 g/mol
Number of moles =0.761 mol
one mole of sulfuric acid contain four mole of oxygen atom.
0.761 mol × 4 = 3.044 mol
1 mole = 6.022×10²³ atoms of oxygen
3.044 mol × 6.022×10²³ atoms of oxygen / 1mol
18.33 ×10²³ atoms
