Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer: $277.91
<u>Step-by-step explanation:</u>
The average of the 2 highest salaried quarters is:

Divide that by 26 (weeks) to find out her average weekly salary:

Multiply that by 55% (0.55) to calculate her weekly unemployment benefit:

Round to the nearest penny --> $277.91
2(4z - 6 - 6) = 170 - 46
2(4z - 12) = 124 |use distributive property: a(b - c) = ab - ac
8z - 24 = 124 |add 24 to both sides
8z = 148 |divide both sides by 8
z = 18.5