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Tresset [83]
3 years ago
12

Grams of cl in 38g of cf3cl

Chemistry
1 answer:
Lerok [7]3 years ago
8 0

Answer:

114 grams

Explanation:

3chlorines per compound*38grams=114

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5 0
3 years ago
When a company is to calculate the selling price of their products, they set up a product calculation. There are five benefits t
iren [92.7K]

Answer:

The pricing strategy is an important element in setting up the selling price of a product.

Explanation:

The pricing strategy is an important consideration while fixing up the selling price of product manufactured. When setting up a selling price of a product, the companies set up product calculation. Businesses should decide the pricing strategy before they advertise the products to the customers.  

There are mainly 5 benefits to the businesses while doing a product calculation. They are:

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5 0
3 years ago
For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .
miss Akunina [59]

Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

[Na⁺] = 0.493 M

[Cl⁻] = 0.493 + 0.314 = 0.807 M

[NH₄⁺] = 0.314 M

The p-values are:

pNa = -log[Na⁺] = -log(0.493) = 0.307

pCl = -log[Cl⁻] = -log(0.807) = 0.093

pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503

7 0
3 years ago
Aluminum has a density of 2.70 g/cm3. what would be the mass of a sample whose volume is 10.0 cm3?
anastassius [24]
Hey there!

Density = 2.70 g/cm³

Volume = 10.0 cm³

Therefore:

Mass = density *  volume

Mass = 2.70 * 10.0

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3 0
3 years ago
How many atoms of oxygen are in 0.100 mol of silicon dioxide?
lys-0071 [83]
1) Silicon dioxide formula: SiO2  ....... 2 is a subscript for the O atom

2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2

3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si

4) Multiply by Avogadro's number: 0.100mol *  6.022*10^23 atoms/mol= 6.02*10^22 atoms

Answer: 6.02*10^22 atoms
3 0
3 years ago
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