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Tresset [83]
3 years ago
12

Grams of cl in 38g of cf3cl

Chemistry
1 answer:
Lerok [7]3 years ago
8 0

Answer:

114 grams

Explanation:

3chlorines per compound*38grams=114

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In Period 2, as the elements are considered from left to
Elza [17]

Answer:

it will option B ,hope it helps

5 0
3 years ago
A brick has a mass of 4.0 kg and the Earth has a mass of 6.0 × 1027 g. Use this information to answer the questions below. Be su
Vedmedyk [2.9K]

Answer:

a) 2.4\times 10^{24} kg is the mass of 1 mole of bricks.

b) 2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

Explanation:

a) Mass of brick = 4.0 kg

1 mole = N_A=6.022\times 10^{23} particles/ atoms/molecules

Mass of N_A bricks :

=6.022\times 10^{23}\times 4.0 kg=2.4088\times 10^{24} kg\approx 2.4\times 10^{24} kg

2.4\times 10^{24} kg is the mass of 1 mole of bricks.

b)

Mass of the Earth = M = 6.0\times 10^{27} kg

Mass of 1 mole of brick = m=2.4\times 10^{24} kg

Let the moles of brick with equal mass of the Earth be x.

m\times x=M

x=\frac{M}{m}=\frac{6.0\times 10^{27}kg}{2.4\times 10^{24} kg}=2.5\times 10^3

2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

7 0
3 years ago
What is the correct formula name for calcium chloride?
Leokris [45]
C. CaCl2 is the correct answer
7 0
3 years ago
Plz help 40 pts i need it<br>thank you
Scorpion4ik [409]

Answer:

answer is in the link because it says my answer contains inappropriate words

Explanation:

7 0
3 years ago
If the pressure inside your ballon is 800mmHG ,and the gas is at body temperature,37 degree Celsius , calculate the number of gr
SpyIntel [72]
With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:

PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles

Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.

0.1529 moles x 29 grams per mole =
4.435 grams of air

The balloon has 4.435 grams of air inside it.

Hope this helps!
6 0
3 years ago
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