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Tresset [83]
3 years ago
12

Grams of cl in 38g of cf3cl

Chemistry
1 answer:
Lerok [7]3 years ago
8 0

Answer:

114 grams

Explanation:

3chlorines per compound*38grams=114

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The amount of heat absorbed when 5.5g of aluminum is heated from 25.0c to 95.0c the specific heat of aluminum is 0.897J/(gc)​
NemiM [27]

Answer:

Q=21.99 kJ

Explanation:

4 0
3 years ago
Respuesta funcion oxido de Mg+2 + O-2
Effectus [21]

Answer:

Mg2 + O2 → 2MgO

Explanation:

Hope this helps!! I got it right.

7 0
2 years ago
A beaker cannot be used for measuring the volume of a liquid because _____.
Ad libitum [116K]

Answer:

Data obtained can't be accurate.

Explanation:

A beaker can't be used for measuring the volume of a liquid because they did not calculate volume of a liquid accurately and precisely. The marks present on the beaker are not accurate, it is just an estimate so by measuring the volume of any liquid using beaker give us a false data so that's why beaker are not used for the measurement of a volume.

4 0
3 years ago
BRAINLIEST TO CORRECT what would the cook time for 2 half-lives of the popcorn?
Svetlanka [38]

Answer:

Pop for two minutes in the microwave, and enjoy the perfect balance of buttery and salty taste in every bite. Try this delicious salty snack for backyard barbeques, movie nights, birthday parties or an office snack. Choose ACT II Butter Popcorn for the best value in popcorn.

Explanation:

3 0
2 years ago
A 25.0 mLsample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>

<em />

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

6.56x10⁻³ moles of CH₃COOH / 0.0250L =

<em>0.263M of CH₃COOH is the concentration of the solution</em>

3 0
3 years ago
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