Answer:
half life = 25 days
Explanation:
Given data:
Total amount of sample = 40 mg
Sample left after 50 days = 10 mg
Half life of P³³ = ?
Solution:
<em>1st step:</em>
when time is zero = 40 mg
1 half life = 40/2 = 20 mg
2 half life = 20/ 2= 10 mg
<em>2nd step:</em>
<em>Elapsed time/ half life = HL</em>
half life = 50 days/ 2
half life = 25 days
Answer:
142.36 kg
Explanation:
volume of water in the lake = surface area x depth
= 18.5 x ( 1760 x 3 )² x 39 ft³
= 2.011 x 10¹⁰ ft³
= 2.011 x 10¹⁰ x 28.3168 liter .
= 56.945 x 10¹⁰ liter .
concentration of mercury = .25 x 10⁻⁶ g / liter
= 25 x 10⁻⁸ g / liter
= 25 x 10⁻¹¹ kg / liter
mass of mercury in the water of lake
= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg
= 142.36 kg .
Where are the answers that apply .. hopes this help :)
What are the names of the two magnetic poles?
Ur answer is
North and South
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Sorry about the holds, copied it from google...