Answer:
good morning everyone I am going to read I am going to read the chapter of nature and who make the stories in Telugu in the latter part of the 9th centuryonce upon a time not stop the story I am going to ask you some few questions and now upon a time upon a time there lived a poor and stitching nice butter is found a strong that shut and when he tried so I
The answer is going to be (a) - oxygen. this is because, for this reaction, charcoal undergoes a combustion reaction, using the oxygen from the surrounding atmosphere to burn to heat, light and CO2.
hope this helps!!
Answer:
2.09 atm
Explanation:
Step 1: Given and required data
- Volume of the vessel (V): 25.0 L
We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.
Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
60.0 g × 1 mol/44.01 g = 1.36 mol
Step 3: Calculate the partial pressure of CO₂
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/ V
P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm
