Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
Answer:
girl look it up like how i do because this makes no sense
Explanation:
The answer is h the reaction produces a lot of thermal energy
Explanation:
The given data is as follows.
T = 298 K,
= -5645 kJ/mol
= -5798 kJ/mol
Relation between
and
are as follows.
=
-5798 kJ/mol = -5645 kJ/mol - 
-153 kJ/mol = -
= 0.513 kJ/mol K
Now, temperature is
= (37 + 273) K = 310 K
Since,
=
= 
= (-5645 kJ/mol - 159.03 kJ/mol)
= -5804.03 kJ/mol
As, change in Gibb's free energy = maximum non-expansion work

= -5804.03 kJ/mol - (-5798 kJ/mol)
= -6.03 kJ/mol
Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.
The chemical reaction involving Mg(OH)2 and HCl is:
<span>Mg(OH)2 + 2HCl
--> MgCl2 + 2H2O</span>
So we see that for every 2 moles of HCl, 1 mole of Mg is
reacted.
Calculating for moles HCl:
moles HCl = 0.300 M * 0.215 L
moles HCl = 0.0645 mol
The moles Mg then is:
moles Mg = 0.0645 mol * (1 / 2)
<span>moles Mg = 0.03225 mol</span>