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IRISSAK [1]
3 years ago
9

What is oxidized in a galvanic cell? O A. The salt bridge O B. The electrolytes O C. The cathode D. The anode​

Chemistry
1 answer:
mr_godi [17]3 years ago
8 0

The Anode is what gets oxidized

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If 1.320 moles of CH4 reacts completely with oxygen, how many grams of H2O can be formed
laiz [17]

Answer:

47.5 g of water can be formed

Explanation:

This is the reaction:

CH₄  +  2O₂  →  CO₂ + 2H₂O

Methane combustion.

In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.

As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.

1.320 mol  .2 = 2.64 moles

Now, we can convert the moles to mass (mol . molar mass)

2.64 mol . 18g/mol = 47.5 g

7 0
3 years ago
Read 2 more answers
Please help!! ASAP Dora rolled a marble down a ramp and recorded the potential energy and kinetic energy of the marble at differ
timofeeve [1]

Answer:

girl look it up like how i do because this makes no sense

Explanation:

6 0
4 years ago
The light produced by fireflies is a complex
mr_godi [17]

The answer is h the reaction produces a lot of thermal energy

7 0
4 years ago
At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.
natka813 [3]

Explanation:

The given data is as follows.

             T = 298 K,          \Delta H^{o} = -5645 kJ/mol

          \Delta G^{o} = -5798 kJ/mol

Relation between \Delta H and \Delta G are as follows.

          \Delta G^{o} = \Delta H^{o} - T \Delta S^{o}    

             -5798 kJ/mol = -5645 kJ/mol - 298 \times \Delta S^{o}

                       -153 kJ/mol = -298 \times \Delta S^{o}

                    \Delta S^{o} = 0.513 kJ/mol K

Now, temperature is 37^{o}C = (37 + 273) K = 310 K

Since,        \Delta G = \Delta H^{o} - T \Delta S^{o}

                            = -5645 kJ/mol - 310 K \times 0.513 kJ/mol K

                            = (-5645 kJ/mol - 159.03 kJ/mol)

                            = -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

            \Delta G = \Delta G_{310 K} - \Delta G_{298 K}

                           = -5804.03 kJ/mol - (-5798 kJ/mol)

                           = -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0
3 years ago
a 0.784 g sample of magnesium is added to a 250 ml flask and dissolved in 150ml of water. magnesium hydroxide obtained from the
Svetach [21]

The chemical reaction involving Mg(OH)2 and HCl is:

<span>Mg(OH)2  +  2HCl  -->  MgCl2  +  2H2O</span>

 

So we see that for every 2 moles of HCl, 1 mole of Mg is reacted.

Calculating for moles HCl:

moles HCl = 0.300 M * 0.215 L

moles HCl = 0.0645 mol

 

The moles Mg then is:

moles Mg = 0.0645 mol * (1 / 2)

<span>moles Mg = 0.03225 mol</span>

5 0
3 years ago
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