Answer:
Acetic
Explanation:
organic chemistry of, pertaining to, or producing vinegar
organic chemistry of or pertaining to acetic acid or its derivatives
The density has been given as the mass of the substance per volume of the solution. The mass of citric acid in the bottle has been 1.22 grams.
<h3>What is percent mass?</h3>
Percent mass can be given as the mass of substance in the total mass of the solution.
The volume of the face serum has been 250 mL, and the density is 0.979 g/mL.
The mass of face serum in the bottle has been:
The total mass of face serum has been 244.75 grams.
The percent mass of citric acid in face serum is 0.5%. This states the presence of 0.5-gram citric acids in 100 grams sample.
The mass of citric acid in the face serum sample is given as:
The mass of citric acid present in 250 mL serum sample has been 1.22 grams.
Learn more about percent mass, here:
brainly.com/question/5394922
Answer:
1. watershed
2. point
3. nonpoint
Explanation:
The land that supplies water to a river system is called a watershed
Pollution from a single, identifiable source is called point
Pollution that is difficult to link to a particular origin is called nonpoint
Explanation:
The oxidation number of Ni is +4
Answer:
Empirical formula: CH₃O
Empirical formula mass = 31 g/mol
Explanation:
Data Given:
Molecular Formula = C₁₀H₃₀O₁₀
Empirical Formula = ?
Empirical Formula mass =
Solution
Empirical Formula:
Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.
So,
The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule
As
C₁₀H₃₀O₁₀ Consist of 10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.
Now
Look at the ratio of these three atoms in the compound
C : H : O
10 : 30 : 10
Divide the ratio by two to get simplest ratio
C : H : O
10/10 : 30/10 : 10/10
1 : 3 : 1
So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1
So the empirical formula will be
Empirical formula of C₁₀H₃₀O₁₀ = CH₃O
Now
To find the empirical formula mass in g/mol
Formula mass:
Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.
**Note:
if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol
So,
As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O
Then Its empirical formula mass will be
CH₃O
Atomic Mass of C = 12
Atomic Mass of H = 3
Atomic Mass of O = 16
Total Molar mass of CH₃O
CH₃O = 12 + 3(1) + 16
CH₃O = 12 + 3 + 16
CH₃O = 31 g/mol
