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2 years ago

What do echolocation and ultrasounds have in common?

1 answer:

8 0

They both are mechanical waves.

Explanation:

Echolocation and ultrasounds are both mechanical waves that require a medium to trace through. They both process and transfer information through waves; the difference is that we humans cannot hear ultrasound waves.

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An airplane used to drop water on brushfires is flying horizontally in a straight line at 180 mi/h at an altitude of 390 ft. Det

Arturiano [62]

Answer:

The water should be released a distance of 1289.88 feet before the plane is on top of the bush fire.

Explanation:

Let's first find the time required for the water to fall down 390 ft onto the bush fire.

Initial Vertical Speed of water = 0

Distance to be covered = 390 ft

Acceleration due to gravity = 32.2 ft/s^2

$s=u*t+\frac{1}{2} (a*t^2)$

$390=0*t+0.5(32.2*t^2)$

t = 4.92 seconds

Thus the water should be dropped 4.92 seconds before the plane is over the bush fire. Now we can also find the distance d at which the pilot should release the water:

d = Speed of plane * time

Speed of plane = 180 / (60 * 60) = 0.05 mile/second

d = 0.05 * 4.92 = 0.246 miles OR 1289.88 feet

Thus, the water should be released a distance of 1289.88 feet before the plane is on top of the bush fire.

3 0

4 years ago

MY LAST ONE<,Brainliest for best answer!

grigory [225]

_Award brainliest if helped!
Mechanical Advantage = Force by Hammer / Force by Nail = 160/40 = 4

8 0

3 years ago

Read 2 more answers

. Egbert is in a rowboat four miles from the nearest point on Egbert a straight shoreline. He wishes to reach a house 12 miles f

swat32

Answer:

$t=\frac{13}{3} =4.33\ mi.hr^{-1}$

Explanation:

Given:

Distance from the shore, $s=4\ mi$

distance of house from the shore, $h=12\ mi$

speed of rowing, $v_r=3\ mi.hr^{-1}$

speed of walking, $v_w=4\ mi.hr^{-1}$

For the least amount of time to reach the house one must row at the nearest point on the shore and then walk from there.

Now the time taken to reach the shore:

$t_s=\frac{s}{v_s}$

$t_s=\frac{4}{3}\ mi.hr^{-1}$

Time taken in walking to house from the shore:

$t_h=\frac{h}{v_w}$

$t_h=\frac{12}{4}$

$t_h=3\ mi.hr^{-1}$

Therefore total time taken:

$t=t_h+t_s$

$t=\frac{13}{3} =4.33\ mi.hr^{-1}$

6 0

3 years ago

What is Power can be define as

Ksju [112]

Power (physics) In physics, power is the rate of doing work, the amount of energy transferred per unit time. In the International System of Units, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the steam engine condenser.

5 0

3 years ago

Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 5.00 s, it rotates 13.9 rad. Du

alisha [4.7K]

Answer:

(a) Angular acceleration is 1.112 rad/s².

(b) Average angular velocity is 2.78 rad/s .

Explanation:

The equation of motion in Rotational kinematics is:

θ = θ₀ + 0.5αt²

Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.

(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:

13.9 = 0 + 0.5α(5)²

α = 1.112 rad/s²

(b) The equation of average angular velocity is:

ω = Δθ/Δt

ω = $\frac{13.9}{5}$

ω = 2.78 rad/s

3 0

4 years ago