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2 years ago

When scientists record the volume of a gas, why do they also record the temperature and the pressure

1 answer:

6 0

They record the temp and Pressure as well because gas will change its volume based on the temperature of the gas and the pressure applied

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How does the doppler effect affect the velocity from a sourse that is approaching you?

Firlakuza [10]

The apparent change in the frequency of a sound caused by the motion of either The Listener or the source of the sound

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3 years ago

A jogger accelerates from rest to 4.86 m/s in 2.43 s. A car accelerates from 20.6 to 32.7 m/s also in 2.43 s. (a) Find the magni

Aleonysh [2.5K]

Explanation:

It is given that,

Initially, the jogger is at rest u₁ = 0

He accelerates from rest to 4.86 m, v₁ = 4.86 m

Time, t₁ = 2.43 s

A car accelerates from u₂ = 20.6 to v₂ = 32.7 m/s in t₂ = 2.43 s

(a) Acceleration of the jogger :

$a=\dfrac{v-u}{t}$

$a=\dfrac{4.86\ m/s-0}{2.43\ s}$

a₁ = 2 m/s²

(b) Acceleration of the car,

$a=\dfrac{v-u}{t}$

$a=\dfrac{32.7\ m/s-20.6\ m/s}{2.43\ s}$

a₂ = 4.97 m/s²

(c) Distance covered by the car,

$d_1=u_1t_1+\dfrac{1}{2}a_1t_1^2$

$d_1=0+\dfrac{1}{2}\times 2\times (2.43)^2$

d₁ = 5.904 m

Distance covered by the jogger,

$d_2=u_2t_2+\dfrac{1}{2}a_2t_2^2$

$d_2=20.6\times 2.43+\dfrac{1}{2}\times 4.97\times (2.43)^2$

d₂ = 64.73 m

The car further travel a distance of, d = 64.73 m - 5.904 m = 58.826 m

Hence, this is the required solution.

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2 years ago

Identify the basic structure of a chemical equation

guajiro [1.7K]

The basic structure would be:

Reactants → Products

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2 years ago

During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapu

ella [17]

Answer:

The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules

Explanation:

The given spring constant of the of the spring, k = 88.0 N/m

The length by which the hose is stretched, x = 4.20 m

For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose

The elastic potential energy, P.E., of a compressed spring is given as follows;

P.E. = 1/2·k·x²

∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²

1/2 × 88.0 N/m × (4.20 m)² = 776.16 J

The work done on the hose = The potential energy given to hose, P.E. = 776.16 J

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2 years ago

What is the velocity of a proton that has been accelerated by a potential difference of 15 kV? (i)\:\:\:\:\:9.5\:\times\:10^5\:m

andre [41]

Answer:

Velocity of a proton, $v=1.7\times 10^6\ m/s$

Explanation:

It is given that,

Potential difference, $V=15\ kV=15\times 10^3\ V$

Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.

Using the conservation of energy as :

$\dfrac{1}{2}mv^2=qV$

q is the charge of proton

m is the mass of proton

$v=\sqrt{\dfrac{2qV}{m}}$

$v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 15\times 10^3\ V}{1.67\times 10^{-27}\ kg}$

$v=1695361.75\ m/s$

$v=1.69\times 10^6\ m/s$

$v=1.7\times 10^6\ m/s$

So, the velocity of a proton is $1.7\times 10^6\ m/s$ . Hence, this is the required solution.

8 0

3 years ago