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3 years ago

What would happen if a rocket ran out of fuel in the Earth's atmosphere?

2 answers:

3 0

It would do exactly what a rock or a frisbee does when you toss it.

After the engines cut off, it couldn't get any more energy from
anywhere, and after that, as it pushed air aside to get through,
and had air molecules scraping against it, those would slowly
rob kinetic energy from it. Sooner or later it would run out of
kinetic energy, start falling, and it would eventually make either
a big 'SPLOOSH' or else a big 'CRUNCH', depending on exactly
where it returned to Earth's surface.

horrorfan [7]3 years ago

3 0

The rocket would fall back down to the surface of earth because there would be nothing propelling it upwards.

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Knowing the definition of work as used by physicists, how can the work done on an object be equal to zero? a. The force and dist

Nuetrik [128]

Answer:

Explanation:

Work is the product of force and distance moved in the direction of force . if no distance, no work is done. Holding a heavy object still means no work is done

4 0

3 years ago

What is the distance between a(-6,3),b(-2,4),c(-8,3)

Schach [20]

Answer:

Explanation:

Appears to be the vertexes of a triangle.

AB = √(-6 - (-2))² + (3 - 4)²) = √17

AC = √(-6 - (-8))² + (3 - 3)²) = 2

BC = √(-2 - (-8))² + (4 - 3)²) = √37

8 0

2 years ago

The objective of baseball is to OUTSCORE your opponent.<br> True or false <br> Help ?

Yuki888 [10]

Answer:

True

Explanation:

The team with the most points at the end of the game is the winner.

5 0

3 years ago

Read 2 more answers

Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge

kramer

Answer:

E = 440816.32 N/C

Explanation:

Given data:

Three point charge of charge equal to +3.0 micro coulomb

fourth point charge = - 3.0 micro coulomb

side of square = 0.50 m

$K =1/4 \pi \epsilon_0 = 8.99 \times 10^9$ N.m^2/c^2

Due to having equal charge on center of square, 2 charge produce equal electric field at center and other two also produce electric field at center of same value

So we have

$E_1 + E_3 = 0$

$E =E_2 + E_4$

$E = 2 E_2$

[ $E_2 =\frac{2\times k \times q}{r^2}$

[ $r= \frac{(0.5^2 + 0.5^2)^2}{2} = 0.35 m$ ]

plugging all value

$E = 2 E_2$

$E = 2 E_2 =\frac{2\times k \times q}{r^2}$

$E = \frac{2 \times 8.99 \times 10^93\times 10^{-6}}{0.35^2}$

E = 440816.32 N/C

3 0

3 years ago

Read 2 more answers

If carbon has an atomic number of 6, how many protons and neutrons are found in the carbon-14 atom? A.

Alex Ar [27]

The correct answer is B. 6 protons and 8 neutrons

Carbon-14 has same atomic number of 6. It has a nucleon number of 14
Atomic number = proton number = 6
Neutron number = nucleon number - atomic number = 14 - 6 = 8

Hope it helped!

5 0

3 years ago