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Kazeer [188]
3 years ago
15

A 100-watt lightbulb radiates energy at a rate of 100 J/s. (The watt, a unit of power, or energy over time, is defined as 1 J/s.

) If all of the light emitted has a wavelength of 520nm, how many photons are emitted per second
Physics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

2.62x10²⁰ photons are emitted per second.

Explanation:

The number of photons emitted per second can be found using the following equation:

E = \frac{hc}{\lambda}   (1)

Where:

h: is the Planck's constant = 6.62x10⁻³⁴ J.s

c: is the speed of light = 3.00x10⁸ m/s

λ: is the wavelength = 520 nm

E: is the energy = 100 J/s

Equation (1) gives the energy for a single photon, so if we have more than one we need to use the term "n" to indicate the number of photons:

E = \frac{nhc}{\lambda}  

By solving the above equation for n we have:

n = \frac{E \lambda}{hc} = \frac{100 J/s*520 \cdot 10^{-9} m}{6.62 \cdot 10^{-34} J.s*3.00 \cdot 10^{8} m/s} = 2.62 \cdot 10^{20} photons/s    

Therefore, 2.62x10²⁰ photons are emitted per second.

 

I hope it helps you!      

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Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are t
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The angles in the triangle are 91 degrees, 53 degrees and 36 degrees respectively.

<h3>What is the cosine rule?</h3>

From the cosine rule we know that;

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(0.78)^2 = (0.47)^2 + (0.62)^2 - 2(0.47 * 0.62)cosC

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Using the sine rule;

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Learn more about triangle:brainly.com/question/2773823

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