A 100-watt lightbulb radiates energy at a rate of 100 J/s. (The watt, a unit of power, or energy over time, is defined as 1 J/s.
1 answer:
Answer:
2.62x10²⁰ photons are emitted per second.
Explanation:
The number of photons emitted per second can be found using the following equation:
(1)
Where:
h: is the Planck's constant = 6.62x10⁻³⁴ J.s
c: is the speed of light = 3.00x10⁸ m/s
λ: is the wavelength = 520 nm
E: is the energy = 100 J/s
Equation (1) gives the energy for a single photon, so if we have more than one we need to use the term "n" to indicate the number of photons:
By solving the above equation for n we have:
Therefore, 2.62x10²⁰ photons are emitted per second.
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Answer
(C).
When there is an angle between the two directions, the cosine of the angle must be considered.
Step by step Solution
The work done by a force is defined as the product of the force and the distance traveled in the direction of motion.
The first answer "Only the component of the force perpendicular to the motion is used to calculate the work" is wrong because, the force perpendicular to motion does no work.
The second choice "If the force acts in the same direction as the motion, then no work is done" is wrong because the work in the direction of the force is .
Fourth answer "A force at a right angle to the motion requires the use of the sine of the angle" is wrong because the meaning that there is no work done in the direction perpendicular to the motion.
The third answer" When there is an angle between the two directions, the cosine of the angle must be considered." is correct because the work is calculated using the force in the direction of the motion. The magnitude of this force is