Answer: 
Explanation:
let this sign be ∅ (titha in degrees)
let coefficient of friction of 0.200 be u
and i be current i= 1.41A
mass m=1.14g/cm m=0.0114g/m
To find the magnetic field from the north will be:
tan ∅= u
∅=
∅=11.3°
The direction:
i L*B cos(∅)= umg
divide both by iLcos(∅) to find B
B= 
where m=
B= 
B= 
The 'Rite of Spring' was composed by Igor Stravinsky.
Answer:
B. 45.0 kg
Explanation:
On earth the object has ;
Mass = 45 kg
acceleration = 9.81 m/s²
On Jupiter, acceleration is 24.79 m/s²
The mass of this object on Jupiter will be 45 kg. It will not change. Mass of an object will only change when you remove part of the object from it or add to it another part. The mass is the same on Earth and on Jupiter. However, due to increased acceleration on Jupiter , the weight will change/ increase because;
Weight = mass * acceleration
<u>On Earth </u>
Weight of the object will be : 45 * 9.81 = 441.45 kg
<u>On Jupiter</u>
Weight of the object will be : 45*24.79 =1115.55 kg
Answer:
D) not enough information to decide
Explanation:
Data provided in the question
The True weight of book stacks = 165 N
Reading of the scale = 165 N
Constant velocity = 2 m/s upward or downward
Based on the above information
If you moved at a constant velocity the scale interprets the same because of the momentum you've got. The scale will change the number only when acceleration is present.
Therefore in the given situation, the option D is correct as it not have enough information for deciding it
