Answer:
weight of astronaut
Explanation:
Given data:
astronaut weight is = 125 lbs
distance of shuttle from surface of earth is 200 mils
we know that
where G, m_1, m_2 are constant value, so we have
radius of earth is 4000 miles
where r_2 = 4000 + 200 = 4200 miles
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness = 92 Mpa√m
yield strength σ = 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length = 1/π(
/ Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection
Answer:
Maximum inside diameter is 68.52 mm.
Explanation:
Apply stress formula to calculate inside diameter of the tube. Take the allowable stress for safe design and maximum inside diameter of the steel tube.
Step1
Given:
Outside diameter is 100 mm.
Tensile load is 500 kN.
Allowable stress is 120 Mpa.
Calculation:
Step2
Inside diameter is calculated by the stress formula as follows:
mm
Thus, the inner diameter is 68.52 mm.