A Transmission Control Protocol (TCP) connection is in working order and both sides can send each other data. What is the TCP so
1 answer:
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Answer:
q₀ = 350,740.2885 N/m
Explanation:
Given
σ = 120 MPa = 120*10⁶ Pa
We can see the pic shown in order to understand the question.
We apply
∑MB = 0 (Counterclockwise is the positive rotation direction)
⇒ - Av*L + (q₀*L/2)*(L/3) = 0
⇒ Av = q₀*L/6 (↑)
Then, we apply
Then, we can get the maximum bending moment as follows
then we get
We get the inertia as follows
We use the formula
σ = M*y/I
⇒ M = σ*I/y
where
If M = Mmax, we have
Answer:
The answer is "Option A".
Explanation:
Series:
Solving the above series:
So, the series is:
Answer:
The horizontal conductivity is 41.9 m/d.
The vertical conductivity is 37.2 m/d.
Explanation:
Given that,
Thickness of A = 8.0 m
Conductivity = 25.0 m/d
Thickness of B = 2.0 m
Conductivity = 142 m/d
Thickness of C = 34 m
Conductivity = 40 m/d
We need to calculate the horizontal conductivity
Using formula of horizontal conductivity
Put the value into the formula
We need to calculate the vertical conductivity
Using formula of vertical conductivity
Put the value into the formula
Hence, The horizontal conductivity is 41.9 m/d.
The vertical conductivity is 37.2 m/d.