Answer:
It stays in place.
Explanation:
An equal amount of force is moving on each side of the cart so it stays the same.
Answer:
(a). The initial velocity is 28.58m/s
(b). The speed when touching the ground is 33.3m/s.
Explanation:
The equations governing the position of the projectile are
![(1).\: x =v_0t](https://tex.z-dn.net/?f=%281%29.%5C%3A%20x%20%3Dv_0t)
![(2).\: y= 15m-\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=%282%29.%5C%3A%20y%3D%2015m-%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
where
is the initial velocity.
(a).
When the projectile hits the 50m mark,
; therefore,
![0=15-\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=0%3D15-%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
solving for
we get:
![t= 1.75s.](https://tex.z-dn.net/?f=t%3D%201.75s.)
Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that
![50m = v_0(1.75s)](https://tex.z-dn.net/?f=50m%20%3D%20v_0%281.75s%29)
which gives
![\boxed{v_0 = 28.58m/s.}](https://tex.z-dn.net/?f=%5Cboxed%7Bv_0%20%3D%2028.58m%2Fs.%7D)
(b).
The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,
![v_x = 28.58m/s.](https://tex.z-dn.net/?f=v_x%20%3D%2028.58m%2Fs.)
the vertical component of the velocity is
![v_y = gt \\v_y = (9.8m/s^2)(1.75s)\\\\{v_y = 17.15m/s.](https://tex.z-dn.net/?f=v_y%20%3D%20gt%20%5C%5Cv_y%20%3D%20%289.8m%2Fs%5E2%29%281.75s%29%5C%5C%5C%5C%7Bv_y%20%3D%2017.15m%2Fs.)
which gives a speed
of
![v = \sqrt{v_x^2+v_y^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bv_x%5E2%2Bv_y%5E2%7D)
![\boxed{v =33.3m/s.}](https://tex.z-dn.net/?f=%5Cboxed%7Bv%20%3D33.3m%2Fs.%7D)
So what you wanna do is take your two givens. 22 and 3. Now you wanna take 22 and divide that by 3. And that gives you 7.33. Now if your answer HAS to be a whole number it'll be 66.
Force = (mass) x (acceleration)
Mass = 2000 grams = 2 kilograms
Force = (2 kg) x (8.3 m/s²)
Force = <em>16.6 Newtons</em>
Solar system is nested nearly 2/3 of the way from the center of the galaxy to the outskirt of the galactic disc.