Answer:
7.5 m
Explanation:
= initial speed of the ball = 8 m/s
= angle of launch = 40° deg
Consider the motion along the vertical direction :
= initial velocity along vertical direction = 
= 8 Sin40 = 5.14 m/s
= acceleration along vertical direction = - 9.8 m/s²
= time of travel
= vertical displacement = - 1 m
Using the kinematics equation
= 1.22 sec
Consider the motion along the horizontal direction :
= initial velocity along horizontal direction = = 8 Cos40 = 6.13 m/s
= acceleration along vertical direction = 0 m/s²
= time of travel = 1.22 sec
= horizontal displacement = ?
Using the kinematics equation
= 7.5 m
The answer is archimedes principle
Answer:
If you are looking for past papers you can search that up and you will find plenty of resources that will help you out.
So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.
<h3>Introduction</h3>
Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :
With the following conditions :
- a = acceleration (m/s²)
= speed after some time (m/s)
= initial speed (m/s)- t = interval of time (s)
<h3>Problem Solving</h3>
We know that :
- a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
- = initial speed = 0 m/s >> the keyword is free fall
- t = interval of time = 2 s
What was asked :
- = speed after some time = ... m/s
Step by step :
So, the speed of the ball after 2 seconds after free fall is 20 m/s.
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