Best Answer:<span> </span><span>The net angle between the direction of flight of the aircraft and the wind in the opposing direction is 20. THe component opposing the aircraft is 2.4*cos 20 KN
= 2400 * 0.9397 = 2255.2622 N. The distance covered is 120 Km
The work done by the aircraft overcoming the wind is
= 2255.2622 * 120000 = 270631464 = 2.71 x 10^8 N
As the question is trickily worded as : the work done on the plane by the air (wind) the answer is -2.71 x 10^8 J . (fourth option)</span>
Answer:
![\boxed{\sf Acceleration \ (a) = 2 \ m/s^{2}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%20Acceleration%20%5C%20%28a%29%20%3D%202%20%5C%20m%2Fs%5E%7B2%7D%7D%20)
![\boxed{\sf Distance \ covered \ (s) = 100 \ m}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%20Distance%20%5C%20covered%20%5C%20%28s%29%20%3D%20100%20%5C%20m%7D%20)
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 20 m/s
Time taken (t) = 10 sec
To Find:
(i) Acceleration (a)
(ii) Distance covered (s)
Explanation:
![\sf (i) \ From \ 1^{st} \ equation \ of \ motion:](https://tex.z-dn.net/?f=%5Csf%20%28i%29%20%5C%20From%20%5C%201%5E%7Bst%7D%20%5C%20equation%20%5C%20of%20%5C%20motion%3A)
![\sf \implies v = u + at](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20v%20%3D%20u%20%2B%20at)
![\sf \implies 20 = 0 + a(10)](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%2020%20%3D%200%20%2B%20a%2810%29)
![\sf \implies 10a = 20](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%2010a%20%3D%2020)
![\sf \implies \frac{10a}{10} = \frac{20}{10}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20%5Cfrac%7B10a%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B20%7D%7B10%7D%20)
![\sf \implies a = 2 \: m/ {s}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20a%20%3D%202%20%5C%3A%20m%2F%20%7Bs%7D%5E%7B2%7D%20)
![\sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:](https://tex.z-dn.net/?f=%5Csf%20%28ii%29%20%5C%20From%20%5C%202%5E%7Bnd%7D%20%5C%20equation%20%5C%20of%20%5C%20motion%3A)
![\sf \implies s = ut + \frac{1}{2} a {t}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20s%20%3D%20ut%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20a%20%7Bt%7D%5E%7B2%7D%20)
![\sf \implies s = (0)(10) + \frac{1}{2} \times 2 \times {(10)}^{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20s%20%3D%20%280%29%2810%29%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%202%20%5Ctimes%20%20%7B%2810%29%7D%5E%7B2%7D%20)
![\sf \implies s = \frac{1}{ \cancel{2}} \times \cancel{2} \times {(10)}^{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20s%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Ccancel%7B2%7D%7D%20%20%5Ctimes%20%20%5Ccancel%7B2%7D%20%5Ctimes%20%20%7B%2810%29%7D%5E%7B2%7D%20)
![\sf \implies s = {10}^{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20s%20%3D%20%20%7B10%7D%5E%7B2%7D%20)
![\sf \implies s = 100 \: m](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20s%20%3D%20100%20%5C%3A%20m)
The answer is A.
p=m/v
p= 240/60
p= 4 g/cm^3
That would be an asteroid
Choices 'a', 'c', and 'd' are true.
In choice 'b', I'm not sure what it means when it says that masses
are 'balanced'. To me, masses are only balanced when they're on
a see-saw, or on opposite ends of a rope that goes over a pulley.
Maybe the statement means that the mass of the nucleus and the
mass of the electron cloud are equal. This is way false. It takes
more than 1,800 electrons to make the mass of ONE proton or
neutron, and the most complex atom in nature only has 92 electrons
in it. So there's no way that the masses of the nucleus and the electrons
in one atom could ever be anywhere near equal.