All categories

3 years ago

What changes were necessary in earth’s atmosphere to allow complex organism to evolve

Physics

2 answers:

jok3333 [9.3K]3 years ago

6 0

Answer:

Earth’s original atmosphere was rich in methane, ammonia, water vapor, and the noble gas neon, but it lacked free oxygen.Oxygen had to become a major atmospheric gas and the ozone layer had to develop.

Zepler [3.9K]3 years ago

5 0

A collision from above such as a meteor and an increase in volcano activity.

You might be interested in

Estimate the force required to bind the two protons in the He nucleus together. (Hint: Model the protons as point charges. Assum

scoray [572]

Answer:

F = 2.30 10⁴ N

Explanation:

The force required to link two gates must be equal to or greater than the electrostatic force of repulsion, because the protons have equal charges.

F = k q₁ q₂ / r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C²

In this case the proton charge is 1.6 10⁻¹⁹ C and the distance between them is approximately the diameter of the core r = 10⁻¹⁵ m

Let's calculate

F = 8.99 10⁹ (1.6 10⁻¹⁹)² / (10⁻¹⁵)²

F = 2.30 10⁴ N

The bond strength must be equal to or greater than this value

3 0

3 years ago

What does a cell use to eliminate a substance that is too large to leave by diffusion?

zysi [14]

<span>a cell eliminates endocytosis.

</span>

6 0

3 years ago

Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in

Elanso [62]

Answer:

kinetic energy

Explanation:

a certain amount of energy is transferred by the kick. The ball gains an equal amount of energy, mostly in the form of kinetic energy.

4 0

3 years ago

Read 2 more answers

A car is traveling with a velocity of 5.5 m/s and has a mass of 1200 kg. What is the kinetic energy?!

vesna_86 [32]

Answer:

Explanation:

The kinetic energy of the car can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the Mass

v is the velocity

From the question we have

$k = \frac{1}{2} \times 1200 \times {5.5}^{2} \\ = 600 \times 30.25$

We have the final answer as

Hope this helps you

3 0

3 years ago

An insulated rigid tank contains 3 kg of H2O in the form of a saturated mixture of liquid and vapor at a pressure of 150 kPa and

Andre45 [30]

Answer:

change in entropy is 1.44 kJ/ K

Explanation:

from steam tables

At 150 kPa

specific volume

Vf = 0.001053 m^3/kg

vg = 1.1594 m^3/kg

specific entropy values are

Sf = 1.4337 kJ/kg K

Sfg = 5.789 kJ/kg

initial specific volume is calculated as

$v_1 = vf + x(vg - vf)$

$= 0.001053 + 0.25(1.1594 - 0.001053)$

$v_1 = 0.20964 m^3/kg$

$s_1 = Sf + x(Sfg)$

$= 1.4337 + 0.25 \times 5.7894 = 2.88 kJ/kg K$

FROM STEAM Table

at 200 kPa

specific volume

Vf = 0.001061 m^3/kg

vg = 0.88578 m^3/kg

specific entropy values are

Sf = 1.5302 kJ/kg K

Sfg = 5.5698 kJ/kg

constant volume so $v_1 - v_2 = 0.29064 m^3/kg$

$v_2 = v_1 = vf + x(vg - vf)$

$=0.29064 = x_2(0.88578 - 0.001061)$

$x_2 = 0.327$

$s_2 = 1.5302 + 0.32 \times 5.5968 = 3.36035 kJ/kg K$

Change in entropy $\Delta s = m(s_2 - s_1)$

=3( 3.36035 - 2.88) = 1.44 kJ/kg

8 0

3 years ago