Answer:
the aquifer’s hydraulic conductivity is K = 10.039 m/day
transmissivity T = 331.287 m/day
the drawdown 100 m away from the well is s = 1.452 m
Explanation:
Given that :
The constant pumps rate Q = 2000 m³/day
R₁ =160 m → H₁ = 249 m
R₂ = 453 m → H₂ = 250 m
The confined aquifer B is 33 m thick
The hydraulic conductivity K =
K =
K =
K = 10.039 m/day
Transmissivity T = K × B
T = 10.039×33
T = 331.287 m/day
TO find the drawdown 100 m away from the well; we have:
K =
H₃ = 248.548 m
Drawdown (s) = H₂ - H₃
s = (250 - 248.548)m
s = 1.452 m
Answer:
The maximum value of the driving force is 1044.01 N.
Explanation:
Given that,
Weight of the object, W = 50 N
Force constant of the spring, k = 210 N/m
The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.
Amplitude, A = 4 cm
We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :
.....(1)
A is amplitude
m is mass,
is angular frequency
Angular frequency is given by :
Equation (1) becomes :
So, the maximum value of the driving force is 1044.01 N.
Answer:
bro i didn't buy any coffee what are you talking about??
Explanation:
Liquid to cup cup to air / hot energy follows cold energy so because of that the cup is losing thermal energy
Answer:
The correct option is;
B. 8 m, because he has to apply less force over a greater distance
Explanation:
In the given question, in order for the student to lift the boxes onto the tuck with less amount of force, he applies the principle of Mechanical Advantage
The mechanical advantage is given by the measure by which a force is amplified through the use of a tool
Given that the work done = The force × The distance, we have
F₁ × d₁ = F₂ × d₂, which gives;
d₁/d₂ = F₂/F₁
Where;
F₁ = The input force
F₂ = The output force
d₁ = The input distance
d₂ = The output distance
The Mechanical advantage, MA = d₁/d₂ = F₂/F₁
Therefore, when the input distance is increased the input force will be reduced for a given output force
SOLUTION:
Total amount of fruit = Total amount of apples + Total amount of pears + Total amount of oranges
Total amount of fruit = 15 / 4 + 29 / 4 + 81 / 8
Total amount of fruit = 30 / 8 + 58 / 8 + 81 / 8
Total amount of fruit = 169 / 8
Total amount of fruit = 21.125 kg
ANSWER:
Therefore, the chief bought 21.125 kg of fruit all together.
Please mark as brainliest if you found this helpful! :)
Thank you <3