Work done by friction?
2 answers:
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Answer
given,
speed of motorist = 25 m/s
distance = 100 m
time to apply break = 0.5 s
a) distance traveled during the reaction time
D = s x t
D = 25 x 0.5
D = 12.5 m
b) the velocity of the motorist at the end of the reaction time is equal to 0 m/s
c) using equation of motion
v² = u² + 2 a s
v = 0 m/s
u = 25 m/s
0² = 25² + 2 x a x 100
a = -3.125 m/s²