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2 years ago

-5x-y=12 3x-5y=4 Linear systems by substitution

Mathematics

1 answer:

alukav5142 [94]2 years ago

4 0

You would do 3 times 5 mines 5 which equals 10 and the you would do 5x12

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Area of the blue shaded region??? please show work

konstantin123 [22]

Answer:

Step-by-step explanation:

you first look at the circle

next you see the numbers in the circle

after that you multiply the numbers together

so, 3 x 7 = 21

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2 years ago

Help me please. I really neeed it

PSYCHO15rus [73]

Answer: You need to put the same shape as it shows there on the top.

Step-by-step explanation: I hope this helped you.

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1 year ago

liz asked charlie to pick up her up a cup of frozen yogurt. she asked for I need to toppings from the six: chocolate chips, gran

Afina-wow [57]

Step-by-step explanation:

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2 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers

What is the value of x in the inequality 7 minus 2x/ -4 + 2 < -x?

Fantom [35]

Maybe it was (7-2x)/-4+2<-x then times 4 both sides -7+2x+8<-4x 2x+1<-4x 6x+1<0 6x<-1 x<-1/6 there we go

8 0

2 years ago