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raketka [301]
3 years ago
12

Write the ion-product expression at equilibrium for each compound: How to enter the correct answer: e.g. silver sulfate (Ag2SO4)

enter this: {Ag+}2{SO42-} don't enter spaces, use square brackets [] not {} or () for concentration and don't worry about subscripting or superscripting [ (1) magnesium carbonate (2) calcium phosphate (3) silver sulfide
Chemistry
1 answer:
enot [183]3 years ago
6 0

Answer:

(1) Magnesium carbonate :-

Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}]

(2) Calcium phosphate :-

Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2]

(3) Silver sulfide :-

Q_{Ag_2S}=[Ag^{+}^2][S^{2-}]

Explanation:

(1) Magnesium carbonate will dissociate as:-

MgCO_3\rightarrow Mg^{2+}+CO_3^{2-}

The expression for the ion-product is as follows:-

Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}]

(2) Calcium phosphate will dissociate as:-

Ca_3(PO_4)_2\rightarrow 3Ca^{2+}+2PO_4^{3-}

The expression for the ion-product is as follows:-

Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2]

(3) Silver sulfide will dissociate as:-

Ag_2S\rightarrow 2Ag^{+}+S^{2-}

The expression for the ion-product is as follows:-

Q_{Ag_2S}=[Ag^{+}^2][S^{2-}]

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