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pav-90 [236]
3 years ago
8

? A body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N

. What is the tension in each wire?
Physics
1 answer:
andriy [413]3 years ago
4 0
So, the weight is supported by the tension in the two wires, but only part of the tension goes in holding the body: the vertical component.

If the angle between the ceiling and the wire is 40 deg, then the vertical component is

T_y = T * sin(40),

There are two wires, so together they do

2*T*sin(40)

And all this holds the weight of the body, so:

2*T*sin(40)=150 ----> T = 75/sin(40)~116.68 N,

Notice how it is larger than 150N (both wires is ~ 233 N), as the angle becomes smaller, there is less tension that is vertical, so one needs more tension to make the vertical component as large as (half) the weight of the body

Hope it helps!

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A 0.75 kg model car is moving west at a speed of 9.0 m/s when it collides head-on with a 2.00 kg model truck that is traveling e
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Answer:

  2.5 m/s east

Explanation:

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The change in momentum of the 0.75 kg model car is ...

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The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.

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The velocity of the model truck after the collision is 2.5 m/s east.

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2 years ago
The free-body diagram of a crate is shown. A free body diagram with 4 force vectors. The first vector is pointing downward, labe
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The net force acting on the crate is determined as 176 N to the left.

<h3>Net force acting on the crate</h3>

The net force acting on the crate is calculated as follows;

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The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

Learn more about net force here: brainly.com/question/14361879

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The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinet
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In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,

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v - velocity of the object

Here,

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m  = 100 kg

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By substituting the given values in the above equation, we get

            K . E=\frac{1}{2} \times 100 \times(11)^{2}=\frac{1}{2} \times 100 \times 121=\frac{12100}{2}=6050\ \mathrm{J}

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