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pav-90 [236]
3 years ago
8

? A body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N

. What is the tension in each wire?
Physics
1 answer:
andriy [413]3 years ago
4 0
So, the weight is supported by the tension in the two wires, but only part of the tension goes in holding the body: the vertical component.

If the angle between the ceiling and the wire is 40 deg, then the vertical component is

T_y = T * sin(40),

There are two wires, so together they do

2*T*sin(40)

And all this holds the weight of the body, so:

2*T*sin(40)=150 ----> T = 75/sin(40)~116.68 N,

Notice how it is larger than 150N (both wires is ~ 233 N), as the angle becomes smaller, there is less tension that is vertical, so one needs more tension to make the vertical component as large as (half) the weight of the body

Hope it helps!

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A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a
AlekseyPX

Answer:

Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day

Part (b) The specific discharge of the flow is 0.0363 m/day

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Part (b) the specific discharge of the flow

V = \frac{Q}{A} = \frac{q}{b} = -K\frac{dh}{dl}\\\\V = -(25 m/d).(\frac{-1.45 m}{1000 m}) = 0.0363 m/day

V = 0.0363 m/day

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Part (d) the time taken for a tracer to travel the distance between the observation wells

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Time = distance / speed

Time = (1000 m) / (0.242 m/day)

Time = 4132.23 days

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Okay, haven't done physics in years, let's see if I remember this.

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