1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pav-90 [236]
3 years ago
8

? A body is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150N

. What is the tension in each wire?
Physics
1 answer:
andriy [413]3 years ago
4 0
So, the weight is supported by the tension in the two wires, but only part of the tension goes in holding the body: the vertical component.

If the angle between the ceiling and the wire is 40 deg, then the vertical component is

T_y = T * sin(40),

There are two wires, so together they do

2*T*sin(40)

And all this holds the weight of the body, so:

2*T*sin(40)=150 ----> T = 75/sin(40)~116.68 N,

Notice how it is larger than 150N (both wires is ~ 233 N), as the angle becomes smaller, there is less tension that is vertical, so one needs more tension to make the vertical component as large as (half) the weight of the body

Hope it helps!

You might be interested in
Vanessa made a list comparing the differences between the outer coverings in plants and animals, but she made a mistake. Read th
GaryK [48]

The skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.

<h3>Why the list is incorrect?</h3>

The list is incorrect because skin is not a reproductive organ and the spines do not attract predators towards each other. Skin protects the body from the outer environment whereas the spines repel the predators from the plant body.

So we can conclude that the skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.

Learn more about skin here: brainly.com/question/306377

#SPJ1

8 0
2 years ago
A rocket moves upward, starting from rest with an acceleration of 25.4 m/s^2 for 3.39 s. It runs out of fuel at the end of the 3
kolbaska11 [484]

Explanation:

Initial speed of the rocket, u = 0

Acceleration of the rocket, a=25.4\ m/s^2

Time taken, t = 3.39 s

Let v is the final velocity of the rocket when it runs out of fuels. Using the equation of kinematics as :

v=u+at

v=25.4\times 3.39=86.10\ m/s    

Let x is the initial position of the rocket. Using third equation of kinematics as :

v^2=u^2+2ax_o

x_o=\dfrac{v^2}{2a}

x_o=\dfrac{86.10^2}{2\times 25.4}=145.92\ m  

Let x_o is the position at the maximum height. Again using equation of motion as :

v^2-u^2=2a(x-x_o)

Now a=-g and v and u will interchange

u^2=2g(x-x_o)

x=x_o+\dfrac{u^2}{2g}

x=145.92+\dfrac{(86.10)^2}{2\times 9.8}

x = 524.14 meters

Hence, this is the required solution.

5 0
3 years ago
In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.1
const2013 [10]

Answer:

6,600N

Explanation:

According to second law of motion, Force = mass × acceleration

If acceleration = change in velocity/time = 15/0.10

Acceleration = 150m/s²

Given mass = 44kg

Force = 44× 150

Force = 6,600N

Magnitude of the average force exerted on the passenger during this time is 6,600N

8 0
3 years ago
Two liquids, A and B, have equal masses and equal initial temperatures. Each is heated for the same length of time over identica
DochEvi [55]

Answer:

So the specific heat of the liquid B is greater than that of A.

Explanation:

Liquid A is hotter than the liquid B after both the liquids are heated identically for the same duration of time from the same initial temperature then according to heat equation,

Q=m.c.\Delta T

where:

m = mass of the body

c = specific heat of the body

\Delta T= change in temperature of the body

The identical heat source supplies the heat for the same amount of time then the quantity of heat supplied is also equal.

So for constant heat, constant mass the temperature change is inversely proportional to the specific of heat of the liquid.

\Delta T=\frac{Q}{m} \times \frac{1}{c}

\Delta T\propto\frac{1}{c}

So the specific heat of the liquid B is greater than that of A.

5 0
3 years ago
A current of 5.0 a flows through an electrical device for 10 seconds. how many electrons flow through this device during this ti
melisa1 [442]
1 Amp = 1 Coulomb/sec
1 Coulomb/sec = 6.25*10^18 electrons/sec

Therefore,
5.0 A = 5 C/s = 5*6.25*10^18 = 3.125*10^19 e/s

In 10 second, number of electrons are calculated as;
Number of electrons through the device = 3.125*10^19*10 = 3.125*10^20 electrons

4 0
3 years ago
Other questions:
  • What sound frequency would the human ear not be able to detect?
    5·2 answers
  • Two boxes are connected to each other by a string as shown in the figure. The 10-n box slides without friction on the horizontal
    5·2 answers
  • The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equ
    7·1 answer
  • g One of the harmonics in an open-closed tube has frequency of 500 Hz. The next harmonic has a frequency of 700 Hz. Assume that
    13·1 answer
  • A pesky rabbit has been feeding on Mrs. Cromwell’s prized flowers. In order to put an end to this she devised the simple trap be
    5·1 answer
  • A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil
    5·1 answer
  • Where do cells get the chemicals needed to synthesize other molecules?
    12·2 answers
  • An isolated conducting sphere has a 16 cm radius. One wire carries a current of 1.0000020 A into it. Another wire carries a curr
    13·1 answer
  • If a circle was flattened by pushing down on it, it would most likely form into the shape of an(1) ___ which has(2)___focal poin
    6·2 answers
  • Physics help please ;-; . An astronaut has a mass of 82.0 kg. What is the astronaut's stationary weight at a position 4230 kilom
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!