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3 years ago

11

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

the visible spectrum. Suppose a particular cone cell absorbs light with a wavelength of 430nm. Calculate the frequency of this light.

1 answer:

Ratling [72]3 years ago

7 0

Answer:

6.97 E 16

Explanation:

Frequency is a function of velocity of light to it's wavelength.

Mathematically written as

F = Velocity / wavelength

Velocity of light = 3 x 10^8

Wavelength =430 nm =430 x 10^-9 m

converting wavelength from nanaometer to meter we divide by 10^9

Frequency = (3 x 10^8)/(430 x10^-9) =6.97 E 16

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If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)

katen-ka-za [31]

Answer:

$\boxed {\boxed {\sf 70,000 \ kg*m/s}}$

Explanation:

Momentum is the product of mass and velocity.

$p=m*v$

The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.

$m= 2000 \ kg \\v= 35 \ m/s$

Substitute the values into the formula and multiply.

$p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s$

The truck's momentum is <u>70,000 kilograms meters per second.</u>

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3 years ago

A billiard ball of mass m moving with speed v1=1 m/s collides head-on with a second ball of mass 2m which is at rest. What is th

Soloha48 [4]

Answer:

The velocity of mass 2m is $v_B = 0.67 m/s$

Explanation:

From the question w are told that

The mass of the billiard ball A is =m

The initial speed of the billiard ball A = $v_1$ =1 m/s

The mass of the billiard ball B is = 2 m

The initial speed of the billiard ball B = 0

Let the final speed of the billiard ball A = $v_A$

Let The finial speed of the billiard ball B = $v_B$

According to the law of conservation of Energy

$\frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2$

Substituting values

$\frac{1}{2} m (1)^2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2$

Multiplying through by $\frac{1}{2}m$

$1 =v_A^2 + 2 v_B ^2 ---(1)$

According to the law of conservation of Momentum

$mv_1 + 2m(0) = mv_A + 2m v_B$

Substituting values

$m(1) = mv_A + 2mv_B$

Multiplying through by $m$

$1 = v_A + 2v_B ---(2)$

making $v_A$ subject of the equation 2

$v_A = 1 - 2v_B$

Substituting this into equation 1

$(1 -2v_B)^2 + 2v_B^2 = 1$

$1 - 4v_B + 4v_B^2 + 2v_B^2 =1$

$6v_B^2 -4v_B +1 =1$

$6v_B^2 -4v_B =0$

Multiplying through by $\frac{1}{v_B}$

$6v_B -4 = 0$

$v_B = \frac{4}{6}$

$v_B = 0.67 m/s$

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3 years ago

Who published the first journal of experimental psychology?

raketka [301]

Answer:

Who published the first journal of experimental psychology?

American Psychological Association published the first journal of experimental psychology.

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Happy labor day!

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2 years ago

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A cyclist moves at a constant speed of 5 m/s if the cyclist does not accelerate during the next 20 seconds he will travel at?

Verizon [17]

5 m/s because the speed is constant

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3 years ago

g A beam of light incident on a smooth flat mirror at an angle of 25o relative to the surface normal of the mirror. What is the

WINSTONCH [101]

To solve this problem we will resort to the concept of angle of incidence and refraction.

Since it is a reflection on a mirror, the angle provided for refraction will be equal to that of the incidence, that is, 25 °

The angle of reflation is always perpendicular to the surface so it is necessary to find the angle with respect to it.

$\theta = 90-25$

$\theta = 65\°$

Therefore the angle of the reflected beam of light made with the surface normal is 65°

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3 years ago