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Anvisha [2.4K]
3 years ago
11

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

the visible spectrum. Suppose a particular cone cell absorbs light with a wavelength of 430nm. Calculate the frequency of this light.
Physics
1 answer:
Ratling [72]3 years ago
7 0

Answer:

6.97 E 16

Explanation:

Frequency is a function of velocity of light to it's wavelength.

Mathematically written as

F = Velocity / wavelength

Velocity of light = 3 x 10^8

Wavelength =430 nm =430 x 10^-9 m

converting wavelength from nanaometer to meter we divide by 10^9

Frequency = (3 x 10^8)/(430 x10^-9) =6.97 E 16

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7. A beam of light converges at a point P. Now a lens is placed in the path of the convergent
Rudiy27

Answer:

Lens at a distance = 7.5 cm

Lens at a distance = 6.86 cm  (Approx)

Explanation:

Given:

Object distance u = 12 cm

a) Focal length = 20 cm

b) Focal length = 16 cm

Computation:

a. 1/v = 1/u + 1/f

1/v = 1/20 + 1/12

v = 7.5 cm

Lens at a distance = 7.5 cm

b.  1/v = 1/u + 1/f

1/v = 1/16 + 1/12

v = 6.86 cm  (Approx)

Lens at a distance = 6.86 cm  (Approx)

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3 years ago
What additional information is needed for velocity that uis not needed for speed?
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Velocity is about direction traveled in comparison to speed which is just distance with out direction
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One way in which elements differ from each other is the structure of the electron cloud in each element’s atoms. In an electron
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What role does carbon dioxide play for all living things​
alexandr1967 [171]

Answer:

carbon dioxide plays an important part in vital plant and animal process, such as photosynthesis and respiration.

Explanation:

8 0
3 years ago
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Heather and Jerry are standing on a bridge 49 mm above a river. Heather throws a rock straight down with a speed of 17 m/sm/s .
lara [203]

Answer:

3.467 s

Explanation:

given,

distance , d = 49 mm = 0.049 m

initial speed of the of the rock, v = 17 m/s

time taken by the Heather rock to reach water

using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = -17 t -\dfrac{1}{2}\times 9.8\times t^2

4.9 t² + 17 t - 0.049 = 0

now,

t_1 = \dfrac{-(17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

t₁ = -3.47 s , 0.0028 s

rejecting negative values

t₁ = 0.0028 s

now, time taken by the ball of Jerry

using equation of motion

s = ut +\dfrac{1}{2}at^2

taking downward as negative

-0.049 = 17 t -\dfrac{1}{2}\times 9.8\times t^2

4.9 t² - 17 t - 0.049 = 0

now,

t_2 = \dfrac{-(-17)\pm \sqrt{17^2 - 4\times 4.9 \times (-0.049)}}{2\times 4.9}

t₂ = 3.47 s ,-0.0028 s

rejecting negative values

t₂ = 3.47 s

now, time elapsed is = t₂ - t₁ = 3.47 - 0.0028 = 3.467 s

5 0
3 years ago
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