3 years ago

At what constant rate of acceleration will a car starting from rest cover 18m in the first 3 seconds?

Physics

1 answer:

irga5000 [103]3 years ago

7 0

69 hehehehe hehehehe here

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initial velocity=u=15m/s
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$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{75-15}{5}$

$\\ \sf\longmapsto Acceleration=\dfrac{60}{5}$

$\\ \sf\longmapsto Acceleration=12m/s^2$

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