At what constant rate of acceleration will a car starting from rest cover 18m in the first 3 seconds?

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

larisa86 [58]

Explanation:

Below is an attachment containing the solution.

7 0

3 years ago

Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t

Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

$v^2=v_0^2+2ax\\$

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

= 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

$a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}$

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

$F_f=ma=(1490kg)(5.55m/s^2)=8271.15N$

Furthermore, you use the relation between the friction force and the friction coefficient:

$F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56$

hence, the friction coefficient is 0.56

6 0

2 years ago

If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you

s344n2d4d5 [400]

Answer:

The friction force is 250 N

Explanation:

The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):

$\sum F=ma$

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:

$\sum F = 0$ (1)

We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

- the pull, forward, F = 250 N

- the friction force, backward, $F_f$

Given (1), we have

$F-F_f = 0$

So the force of friction must be equal to the pull:

$F=F_f = 250 N$

8 0

2 years ago

While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke

3241004551 [841]

Answer:

The right shoe

Explanation:

Both shoes have the same speed.

5 0

3 years ago

Calculate the wave number for the infrared absorption of D35Cl when there is a transition from v=0 to v=1 (Unit: cm^-1, 4-digit

AVprozaik [17]

Answer:

wave number = 0.3348 * 10⁻⁸ cm⁻¹

Explanation:

Given data:

K = 4.808 * 10^2 N/m

<u>Determine the wave number for the infrared absorption</u>

considering vibrational Spectre

k' = 2n / λ ---- ( 1 )

λ = c / v ----- ( 2 )

v = √k / u --- ( 3 )

where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency, k = force constant, u = reduced mass

u = 1.90415 for D35Cl

Input equations 2 and 3 into equation 1 to get the final equation

K' = 2n/c * √k / u

= ( 2 * 3.14 ) / 2.98 * 10^8 ] * (√ 4.808 * 10^2 / 1.90415 )

= 33.486 * 10⁻⁸ m⁻¹ ≈ 0.3348 * 10⁻⁸ cm⁻¹

6 0

3 years ago