Answer: Student 2
Explanation: Iron nail and a paperclip are conductors because they are made of metal. A rock, rubber band, and wooden stick are insulators because they cannot conduct electricity.
I believe its newtons 3rd law for every action there is an equal but opposite reaction since the squid is moving foward by shooting the water its pushing the squid back as its reaction. Hope this helped !
Answer:
Efficiency = 52%
Explanation:
Given:
First stage
heat absorbed, Q₁ at temperature T₁ = 500 K
Heat released, Q₂ at temperature T₂ = 430 K
and the work done is W₁
Second stage
Heat released, Q₂ at temperature T₂ = 430 K
Heat released, Q₃ at temperature T₃ = 240 K
and the work done is W₂
Total work done, W = W₁ + W₂
Now,
The efficiency is given as:
![\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}](https://tex.z-dn.net/?f=%5Ceta%3D%5Cfrac%7B%5Ctextup%7BTotal%5C%20work%5C%20done%7D%7D%7B%5Ctextup%7BEnergy%5C%20provided%7D%7D)
or
Work done = change in heat
thus,
W₁ = Q₁ - Q₂
W₂ = Q₂ - Q₃
Thus,
![\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}](https://tex.z-dn.net/?f=%5Ceta%3D%5Cfrac%7B%28Q_1-Q_2%29%5C%20%2B%5C%20%28Q_2-Q_3%29%7D%7BQ_1%7D%7D)
or
![\eta=1-\frac{(Q_1-Q_3)}{Q_1}}](https://tex.z-dn.net/?f=%5Ceta%3D1-%5Cfrac%7B%28Q_1-Q_3%29%7D%7BQ_1%7D%7D)
or
![\eta=1-\frac{(Q_3)}{Q_1}}](https://tex.z-dn.net/?f=%5Ceta%3D1-%5Cfrac%7B%28Q_3%29%7D%7BQ_1%7D%7D)
also,
![\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}](https://tex.z-dn.net/?f=%5Cfrac%7BQ_1%7D%7BT_1%7D%3D%5Cfrac%7BQ_2%7D%7BT_2%7D%3D%5Cfrac%7BQ_3%7D%7BT_3%7D)
or
![\frac{T_3}{T_1}=\frac{Q_3}{Q_1}](https://tex.z-dn.net/?f=%5Cfrac%7BT_3%7D%7BT_1%7D%3D%5Cfrac%7BQ_3%7D%7BQ_1%7D)
thus,
![\eta=1-\frac{(T_3)}{T_1}}](https://tex.z-dn.net/?f=%5Ceta%3D1-%5Cfrac%7B%28T_3%29%7D%7BT_1%7D%7D)
thus,
![\eta=1-\frac{(240\ K)}{500\ K}}](https://tex.z-dn.net/?f=%5Ceta%3D1-%5Cfrac%7B%28240%5C%20K%29%7D%7B500%5C%20K%7D%7D)
or
![\eta=0.52](https://tex.z-dn.net/?f=%5Ceta%3D0.52)
or
Efficiency = 52%
Answer:
16.6 N
Explanation:
m = 0.52 kg, v₀ = 0, v = 8.6 m/s, t = 0.27 s
a = (v - v₀)/t
F = ma = m(v - v₀)/t = 0.52 (8.6 - 0)/0.27 = 16.6 N
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2
where:Ø - angular displacement w1 - initial angular velocity t - time ã - angular acceleration
128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1
w1 = wo + ãt
w1 - final angular velocity
wo - initial angular velocity
18 = 0 + 4.5t t = 4 s