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Alenkinab [10]
4 years ago
6

. As we increase the quantum number of an electron in a one-dimensional, infinite potential well, what happens to the number of

maximum points in the probability density function?
It increases.

It decreases.

It remains the same
Physics
1 answer:
Natalija [7]4 years ago
8 0

Answer:

It increases.

Explanation:

For the electron to escape the photon needs energy is equal to the difference between initial and its non quantised region energy , then only it will be able to escape finite well.

E ∝ n^2

n= energy state quantum number

so if , n increases maximum point of probability density increases.

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Some strongly electric fish will stun prey by generating an electric current that runs
Bezzdna [24]

Answer: when fish is stunning it's prey it's cause electric shock to the prey that's make it die and be able to be utilized by electric eel(fish generate electric surround)

4 0
3 years ago
Please help me,its urgent!!
GREYUIT [131]

Test:

Performing a Litmus Test

Result:

Litmus paper gives the user a general indication of acidity or alkalinity as it correlates to the shade of red or blue that the paper turns.

  • To test the pH of a substance, dip a strip of litmus paper into the solution or use a dropper or pipette to drip a small amount of solution onto the litmus paper.
  • Blue litmus paper can indicate an acid with a pH between 4 and 5 or lower.
  • Red litmus paper can show a base with a pH greater than 8.
  • If a solution has a pH between 5 and 8, it will show little color change on the litmus paper.
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4 0
3 years ago
Please need help on this not too sure on this
n200080 [17]

Answer:

the last one

Explanation:

Because it is a magnifying glass, it magnifies the object and makes it bigger than it appears

3 0
3 years ago
Read 2 more answers
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

7 0
3 years ago
Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball
Bond [772]
This problem involves Newton's universal law of gravitation and the equation to follow would be.

F = GM₁M₂/r²  

Given: M₁ = 0.890 Kg;  M₂ = 0.890 Kg;  F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²

Solving for distance r = ?

r = √GM₁M₂/F

r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N

r = 0.81 m 
6 0
4 years ago
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