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nlexa [21]
3 years ago
7

How many times should the power develop by the engine of a ship increases to double is velocity i the resistance of the water to

the motion of the ship increases in proportion to the square of the velocity.
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

If the ship speed is doubled, then the power developed is 8 times the initial value.

Explanation:

ship power is roughly proportional to the cube of the speed, so

P ∝ v³

If the speed is doubled, then the power developed becomes

P  ∝ (2)³ = 8 times

Therefore, if the ship speed is doubled, then the power developed is 8 times the initial value.

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A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
If an ideal gas does not exist then why laws were stated?
mihalych1998 [28]
That is because it is impossible to create a law for the behavior of every single different gas, so creating laws for an ideal gas helps us understand the basic nature of gasses which might or might not differ slightly or a lot. By understanding how an ideal gas works, we can understand how a normal gas works.
5 0
3 years ago
Sunburn is caused by ultraviolet light waves having a frequency of around 10^16 Hz. What is their wavelength if the speed of lig
Taya2010 [7]

Given:\\f=10^{16}Hz\\c=3\cdot 10^8\frac{m}{s} \\\\Find:\\\lambda =?\\\\Solution:\\\\\lambda = \frac{c}{f} \\\\\lambda= \frac{3\cdot 10^8\frac{m}{s}}{10^{16}Hz} =3\cdot 10^{-8}m = 30nm

5 0
3 years ago
Ayuda por favor !
Mrrafil [7]

La respuesta es 3 ohmios

Resistencia total = (1/12 + 1/4) ⁻¹

= (1/3) ⁻¹

= 3 ohmios

Por ejemplo, dos resistencias, R1 y R2 están en serie, la resistencia combinada es R1 + R2.

Cuando se conecta en paralelo, la resistencia total es el recíproco de (1 / R1 + 1 / R2)

En este caso las resistencias están en paralelo

Espero que esto ayude, que tengas un día bendecido!

8 0
3 years ago
A periodic transverse wave has an amplitude of 0.20 meter and a wavelength of 3.0 meters. If the frequency of this wave is 12 Hz
skelet666 [1.2K]

Answer:

36 m/s

Explanation:

The speed of wave is a product of wavelength and frequency, expressed as s=fw where f is frequency in Hz and w is wavelength. Wavelength is the distance between successive crests while frequency is also the reciprocal of time. Amplitude has no effect on the velocity of waves. Substituting frequency with 12 Hz and wavelength with 3 m then the speed will be

S=3*12=36 m/s

Therefore, the speed is 36 m/s

5 0
3 years ago
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