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Elenna [48]
3 years ago
9

You hit a hockey puck and it slides across the ice at nearly a constant speed.Is a force keeping it in motion?Explain.

Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Explanation:

When the puck is sliding on the ice, there is no force being exerted on the puck to keep it moving forward. Instead, inertia keeps the puck moving forward. Friction between the puck and the ice gradually slows the puck down. You hit a hockey puck and it slides across the ice at nearly a constant speed

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What characteristic do the metals iron, nickel, and cobalt share?
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They are all conductors.
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A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon
Yuri [45]

consider the motion in y-direction

v₀ = initial velocity = 0 m/s

a = acceleration = g = - 9.8 m/s²

t = time

v = final velocity at any time "t"

velocity at any time is given as

v = v₀ + at

v = 0 + (- 9.8) t

v = (- 9.8) t

so at t = 1  , v = (- 9.8) (1) = - 9.8 m/s

at t = 2  , v = (- 9.8) (2) = - 19.6 m/s

at t = 3  , v = (- 9.8) (3) = - 29.4 m/s     and so on



Y₀ = initial position where the marble was dropped from = 0 m

Y = final position at any time "t"

final position at any time "t" is given as

Y = Y₀ + v₀ t + (0.5) a t²

Y = 0 + (0) t + (0.5) (-9.8) t²

Y = - 4.9 t²

at t = 1 , Y = - 4.9 (1)² = - 4.9 m

at t = 2 , Y = - 4.9 (2)² = - 19.6 m

at t = 3 , Y = - 4.9 (3)² = - 44.1 m  

and So on

6 0
3 years ago
A player kicks a soccer ball in a high arc toward the opponent's goal. When the soccer ball reaches its maximum height, how does
Artyom0805 [142]

Answer:

The speed of the soccer ball at height point is less than its initial speed

Explanation:

The initial velocity of the soccer can be written in vector form as

v_{i = v cos θ î + v sin θ j

where v_{i  is initial velocity of the ball

           v is the initial speed of the ball

Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,

v_{x} = v cos θ

v_{y} = v sin θ

At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,

v_{m} = v cos θ j

where, v_{m} is velocity of the soccer ball at maximum height

5 0
4 years ago
You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s
Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

W = \dfrac{1}{2}kx^2

5 = \dfrac{1}{2}kx^2............(1)

Work done in compression of spring at higher setting

W' = \dfrac{1}{2}kx'^2

W'= \dfrac{1}{2}k(2x)^2

W'= 4\times \dfrac{1}{2}kx^2

W'= 4\times W

from equation (1)

W'= 4\times 5

    W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0
3 years ago
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