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3 years ago

A tornado moving cross a street with a force of 600 N pushes a trailer a distance of 25 m.

Physics

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

<em>W = 15,000 Joule</em>

Explanation:

<u>Mechanical Work </u>

Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

If both the force and displacement are parallel, then we can use the scalar formula:

W=F.s

Where

F =Magnitude of the force

s = magnitude of the displacement

The tornado moved a trailer with a force of F=600 N for a distance of s=25 m. The work done was:

W = 600 N * 25 m

W = 15,000 Joule

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A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it? For water, Lf=334 kJ/kg and Lv=2257 kJ/kg

Aleonysh [2.5K]

Heat required to change the phase of ice is given by

Q = m* L

here

m = mass of ice

L = latent heat of fusion

now we have

m = 45 kg

L = 334 KJ/kg

now by using above formula

$Q = 45 * 334 * 10^3$

$Q = 1.5 * 10^7 J$

In KJ we can convert this as

$Q = 1.5 * 10^4 kJ$

so the correct answer is D option

7 0

3 years ago

Read 2 more answers

A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre

AleksandrR [38]

Answer:

A) 1568.60 Hz

B) 1437.15 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

$f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\$

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

$f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz$