The mass left by the jar of tea is 630 g
<u>Explanation:</u>
<u>Solving the problem:</u>
<u>1. Heat gained by the Ice</u>
To find the value of the Q
<u>Q=Heat gained by the Ice</u>
<u>Q=m c delta T</u>
Q=0.120kg x 2090 J/kg . ° C. (31°C-0°C)
Q= 774.8 J
<u>2. Heat Lost by the water</u>
Q=<u>Heat Lost by the water</u>
Q=m c deltaT
Q=
0.173 kg x 4186 J/kg . ° C.(31°C-31.6°C)
Q=-434.50J
The results obtained for the heat is
Ice from 0 degC -> 31degC = Q= 774.8 J
water from 31.6 degC -> 31 degC = Q= 434.50J
<u>3.To find the mass</u>
We need to use enthalpy of fusion of ice which is 334 J/g.
The mass of ice remaining at the end has to be less than 138 g.
Mass=(138- M) x 334 (enthalpy) =
434.50J( heat loss by water)
Mass= 138-M=-434.50-334
Mass=138-M=768.5
Mass=630 g
The mass left by the jar of tea is 630 g