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amm1812
4 years ago
8

A jar of tea is placed in sunlight until it

Physics
1 answer:
olasank [31]4 years ago
7 0

The mass left by the jar of tea is 630 g

<u>Explanation:</u>

<u>Solving the problem:</u>

<u>1. Heat gained by the Ice</u>

To find the value of the Q

<u>Q=Heat gained by the Ice</u>

<u>Q=m c delta T</u>

Q=0.120kg  x  2090 J/kg . ° C. (31°C-0°C)

Q= 774.8 J

<u>2. Heat Lost by the water</u>

Q=<u>Heat Lost by the water</u>

Q=m c deltaT

Q= 0.173 kg x  4186 J/kg . ° C.(31°C-31.6°C)

Q=-434.50J

The results obtained for the heat is

Ice from 0 degC -> 31degC = Q= 774.8 J

water from 31.6 degC -> 31 degC = Q= 434.50J

<u>3.To find the mass</u>

We need to use enthalpy of fusion of ice which is 334 J/g.

The mass of ice remaining at the end has to be less than 138 g.

Mass=(138- M) x 334 (enthalpy) = 434.50J( heat loss by water)

Mass= 138-M=-434.50-334

Mass=138-M=768.5

Mass=630 g

The mass left by the jar of tea is 630 g

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