Matthias Jacob Schleiden was a German botanist who, with Theodor Schwann, cofounded the cell theory. In 1838 Schleiden defined the cell as the basic unit of plant structure, and a year later Schwann defined the cell as the basic unit of animal structure.

Explanation:

4 0

3 years ago

A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r

mojhsa [17]

To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where $n_{products} < n_{reactants}$ ,

then = $K_p < K_c$

It's because $\Delta n$ is negative, which places (RT) in the denominator. This is how the equation will now appear.

$K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}$

Here you can observe the value of $K_c$ is greater than $K_p$ . To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about equilibrium

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6 0

2 years ago

Are electrons exchanged between ionic or covalent bonds

Rudik [331]

Answer:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals.

3 0

3 years ago

Read 2 more answers

Mixing solutions of sodium hydroxide and rubidium nitrate will cause rubidium hydroxide to precipitate. You have a 1.50 mol/L so

Crazy boy [7]

Answer:

97.6 mL of Sodium Hydroxide and 732 mL of Rubidium Nitrate are needed to make 15 g of Rubidium hydroxide.

Explanation:

The chemical reaction described in the question can be given as

NaOH + RbNO₃ → RbOH + NaNO₃

We want to find the amount of each reactant that reacted to give 15 g of RbOH

Amount of RbOH produced from the reaction = 15 g,

We first convert to number of moles, to be able to obtain the number of moles of each reactant from the stoichiometric balance of the reaction.

Number of moles = (Mass)/(Molar Mass)

Molar Mass of RbOH = 102.475 g/mol

Number of moles of RbOH produced from the reaction = (15/102.475) = 0.1464 moles.

Note that from the stoichiometric balance of the reaction,

1 mole of RbOH was produced from 1 mole of RbNO₃

And

1 mole of RbOH was produced from 1 mole of NaOH.

So,

0.1464 mole of RbOH will be produced from 0.1464 mole of RbNO₃

And

0.1464 mole of RbOH will be produced from 0.1464 mole of NaOH

Note that,

Number of moles = (Concentration in mol/L) × (Volume in L)

For RbNO₃,

Number of moles = 0.1464 mole

Concentration in mol/L = 0.200 mol/L

Volume in L = ?

0.1464 = 0.2 × (Volume in L)

Volume in L = (0.1464/0.20) = 0.732 L = 732 mL

For NaOH,

Number of moles = 0.1464 mole

Concentration in mol/L = 1.50 mol/L

Volume in L = ?

0.1464 = 1.50 × (Volume in L)

Volume in L = (0.1464/1.50) = 0.0976 L = 97.6 mL

Hope this Helps!!!

4 0

3 years ago