I'm afraid you're not paying attention. This question is loaded with
all the important words, and you don't recognize Newton's second
law of motion. Didn't you notice the "force", "acceleration", and
"mass" all over the place in there ?

Newton's 2nd law: Force = (mass) x (acceleration)

The answer is going to be 'mass', so let's divide
each side of Newton's law by 'acceleration':

   Mass = (force) / (acceleration)

Now, just write in the numbers that the question gave you:

      force = 60 newtons
   acceleration = 4 m/s²

Here's the equation again:    Mass = (force) / (acceleration)

   = (60 N) / (4 m/s²)

   = 15 kg .

3 0

4 years ago

A smooth circular hoop with a radius of 0.800 m is placed flat on the floor. A 0.300-kg particle slides around the inside edge o

Marrrta [24]

Answer:

a)11.25 J

b)Number of revolution = 1

Explanation:

Given that

Radius ,r= 0.8 m

m= 0.3 kg

Initial speed ,u= 10 m/s

final speed ,v= 5 m/s

Initial energy

$KE_i=\dfrac{1}{2}mu^2$

$KE_i=\dfrac{1}{2}0.3\times 10^2$

KEi= 15 J

Final kinetic energy

$KE_f=\dfrac{1}{2}mv^2$

$KE_f=\dfrac{1}{2}0.3\times 5^2$

KEf=3.75 J

The energy transformed from mechanical to internal = 15 - 3.75 J = 11.25 J

The minimum value to complete the circular arc

$V=\sqrt{r.g}$

Now by putting the values

$V=\sqrt{0.8\times 10}$

V= 2.82 m/s

So kinetic energy KE

$KE=\dfrac{1}{2}mV^2$

$KE=\dfrac{1}{2}0.3\times 2.82^2$

KE=1.19 J

ΔKE= KEi - KE

ΔKE= 15- 1.19 J

ΔKE=13.80 J

The minimum energy required to complete 2 revolutions = 2 x 11.25 J

= 22.5 J

Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.

Number of revolution = 1

4 0

3 years ago

Báo cáo thực hành

pishuonlain [190]

Answer:

which language is this

Explanation:

4 0

3 years ago

If the magnets are brought close together, they will

murzikaleks [220]

It depends on which side. Opposites attract, so north and south would attract to each other and collide, while north and north or south and south would go away from eachother.

7 0

3 years ago

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