Answer:
201.76266192 m
Explanation:
Distance traveled in the horizontal direction = 153 m
In the vertical direction the distance traveled
Total distance from pythagoras theorem
The total distance the boat will travel to reach the opposite shore is 201.76266192 m
Answer: Period = 0.2 seconds; frequency = 5Hz
Explanation:
Number of oscillations = 50
Time required = 10 seconds
Period (T) = ?
Frequency of the oscillations (F) = ?
A) Recall that frequency is the number of oscillations that the mass spring system completes in one second.
i.e Frequency = (Number of oscillations / time taken)
F = 50/10 = 5Hz
B) Period, T is inversely proportional to frequency. i.e Period = 1/Frequency
T = 1/5Hz
T = 0.2 seconds
Thus, the the period and frequency of the oscillations are 0.2 seconds and 5Hz respectively.
Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :
p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s
The net force performs a total amount of work equal to
(45 N) (0.80 m) = 36 J
on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have
W = ∆K = 1/2 mv²
since the bullet starts at rest, where m = its mass and v = its final velocity.
Solve for v :
36 J = 1/2 (0.0050 kg) v² ⇒ v = 120 m/s
