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Troyanec [42]
3 years ago
12

A particle with 10 protons, 11 neutrons, and 12 electrons has a mass number of:

Chemistry
1 answer:
garik1379 [7]3 years ago
7 0

For any given element the mass number can be found by adding the protons and the neutrons.

In this case its 10 protons plus 11 neutrons which gives us 21 as the mass number.

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30. a. How do the properties of metals differ from those
Ahat [919]

Explanation:

Metals are elements that ionized by loss of electrons.

Ionic and molecular compounds are usually non-metals.

Properties of metals:

  • Metals have free mobile electrons and the metallic bonding ensures that.
  • They are usually electropositive and freely looses their electrons.
  • None of the metal is soluble without a chemical change occurring.
  • They are ductile and malleable.
  • Metals are good conductor or heat and electricity in their free uncombined state.
  • They are lustrous.

B. The specific property of metals accountable for their unusual electrical conductivity is due to the presence of free mobile electrons in their lattices.

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3 0
3 years ago
Write insoluble or soluble solution for the following mixtores<br>1<br>2<br>3<br>4<br>5<br>​
dimaraw [331]

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6 0
2 years ago
8 points
butalik [34]

Answer:

1.3 meters

Explanation: use newton third law equation.

5 0
3 years ago
A 1.0 mole sample of fluorine gas at 25 °C has an average molecular velocity of 415 m/s. What is the total KE of the gas sample?
Mariana [72]

The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

  • KE is the kinetic energy
  • m is the mass
  • v is the velocity

<h3>How to determine the mass of the fluorine gas</h3>
  • Molar mass of fluorine gas = 38 g/mol
  • Mole of fluorine gas = 1 mole
  • Mass of fluorine gas = ?

Mass = mole × molar mass

Mass of fluorine gas = 1 × 38

Mass of fluorine gas = 38 g

<h3>How to determine the KE of the gas sample</h3>
  • Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
  • Velocity (v) = 415 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.038 × 415²

KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

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4 0
2 years ago
Please help fast thank yuo
Masteriza [31]

Answer:

what is your question tell may i can help you

7 0
2 years ago
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