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torisob [31]
3 years ago
9

Match the different methods used for calculating revenue and profit to the formulas used for calculating them. total revenue ave

rage revenue marginal revenue gross profit net profit
Chemistry
1 answer:
Simora [160]3 years ago
3 0

Answer:

See explanation below

Explanation:

1) Total Revenue:

Total revenue refers to the total amount of income that is generated when a company sells or offers their service.

It is usually calculated as the product of the product or services sold by the quantity.

It is calculated by ;

TR = Q * P

Where TR = Total Revenue

Q = Quantity

P = Price

2.) Average Revenue:

Average revenue is the revenue gotten by a company per unit of output sold. It is calculated by:

AR = TR / Q

Where AR = Average Revenue

TR = Total Revenue

Q. = Quantity

3.) Marginal Revenue:

This is the net revenue that is generated by selling an additional unit of commodity; which is the change in total revealer unit. It is calculated by:

MR = change in Total Revenue / change in Quantity

Where MR = Marginal Revenue

4.) Gross Profit:

Gross profit is the amount of revenue left after factoring out the cost of production and sales and servicing.

It is calculated by subtracting revenue from the cost of goods sold -

Gross Profit = Revenue - Cost of goods sold

Net Profit:

Net profit is the amount of money a company has left after subtracting all interests, tax expenses and cost.

It is calculated by;

Net Profit = Gross Profit - Expenses

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A 25.0 ml sample of 0.723 m hclo4 is titrated with a 0.27303 m koh solution. the h3o+ concentration after the addition of 66.2 m
tia_tia [17]
This doesn't need an ICE chart. Both will fully dissociate in water.

Assume HClO4 and KOH reacts with one another. All you need to do is determine how much HClO4 will remain after the reaction. Calculate pH.

Step 1:

write out balanced equation for the reaction

HClO4+KOH ⇔ KClO4 + H2O

the ratio of HClO4 to KOH is going to be 1:1. Each mole of KOH we add will fully react with 1 mole of HClO4

Step 2:

Determining the number of moles present in HClO4 and KOH

Use the molar concentration and the volume for each:
25 mL of 0.723 M HClO4

Covert volume from mL into L:
25 mL * 1L/1000mL = 0.025 L

Remember:

M = moles/L so we have 0.025 L of 0.723 moles/L HClO4

Multiply the volume in L by the molar concentration to get:

0.025L x 0.723mol/L = 0.0181 moles HClO4.

Add 66.2 mL KOH with conc.=0.273M
66.2mL*1L/1000mL = .0662 L
.0662L x 0.273mol/L = 0.0181 moles KOH

Step 3:

Determine how much HClO4 remains after reacting with the KOH.

Since both reactants fully dissociate and are used in a 1:1 ratio, we just subtract the number of moles of KOH from the number of moles of HClO4:

moles HClO4 = 0.0181; moles KOH = 0.0181, so 0.0181-0.0181 = 0

This means all of the HClO4 is used up in the reaction.

If all of the acid is fully reacted with the base, the pH will be neutral = 7.

Determine the H3O+ concentration:

pH = -log[H3O+]; [H3O+] = 10-pH = 10-7

The correct answer is 1.0x10-7.
3 0
3 years ago
Read 2 more answers
Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
Aliun [14]

Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

5 0
3 years ago
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which of the elements below has a smaller atomic radius. element1: 1s2 2s2 2p4 element2: 1s2 2s2 2p5​
stiks02 [169]

Answer:

both are same give different number

8 0
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