All categories

3 years ago

Chemical properties of acetic acid

1 answer:

7 0

I don't think that there is a chemical property of it. here are the physical properties:
Melting Point:
16.6°C
Boiling Point:
117.9°C<span>
</span>
<span>Density (g/cm3):
</span>
1.0446 at 25°C 9

<span>1 atm pressure</span>

You might be interested in

If 3. 5 grams of ni are reacted with excess oxygen to form nickel oxide unser standard state conditions, what is the entropy cha

Mashutka [201]

Entropy Change is the measure of the randomness of the thermodynamic system. The entropy change for the reaction is -49.3 J/K.

<h3>What is the change in entropy?</h3>

Entropy change is the ratio of the heat transfer of the system to the absolute temperature of the system.

The entropy of nickel = 182.1 J/mol. K

The entropy of oxygen = 205.0 J/mol. K

The entropy of nickel oxide = 37.99 J/mol. K

Entropy change is calculated as:

$\begin{aligned}\Delta \rm S &= 2(37.99)-2(182.1)-205\\\\&= 75.98 - 364.2 - 205\\\\&= -493.22 \end{aligned}$

Therefore, -49.3 J/K is the entropy change.

Learn more about entropy change here:

brainly.com/question/1301642

#SPJ4

8 0

2 years ago

What is the texture and appearance of oil

alexgriva [62]

Explanation:

yellow and slick

8 0

4 years ago

The first step in the formation of all three products is the loss of the ots leaving group to give a carbocation intermediate. t

lina2011 [118]

The carbocation stabilized by resonance structure and thereby lowers the energy of the carbocation, hydrogen will add to the carbon in the double bond that produces delocalization of electrons.

<h3>What is carbocation?</h3>

A carbocation is a molecule in which a carbon atom has a positive charge and three bonds.

In general, electrons are stabilized by delocalization. The stabilization energy engendered by delocalization over more than two atoms is called the resonance stabilization energy or simply the resonance energy. The greater the extent of electron delocalization the greater the resonance stabilization.

Learn more about the carbocation here:

brainly.com/question/19168427

#SPJ1

4 0

2 years ago

Please help with this one

bonufazy [111]

Answer: B) increasing temperature

Explanation:

3 0

3 years ago

Read 2 more answers

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$

3 0

3 years ago