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amm1812
3 years ago
7

How does the speed of light depend on an observer's frame of reference?

Physics
1 answer:
Irina-Kira [14]3 years ago
5 0

The speed of light is the same in all frames of reference, regardless of the frame of reference or how it's moving.

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What does the term conclude mean
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Answer:

Meaning to bring ssomething to an end

Explanation:

For example if someone is wrapping up an essay a common phrase used is "In conclusion" (conclude beinf that base word) when restating their arguement.

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pulling one of the balls away from the other. To pull a ball away, click on the ball and drag it. What happens to the force arro
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Gravity.: Gravity is the force that acts at a right angle to the path of an orbiting object.
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A 5.6 MeV (kinetic energy) proton enters a 0.39 T field, in a plane perpendicular to the field. What is the radius of its path?
Kisachek [45]

Answer:

the radius of the protons path is r = 0.85 m.

Explanation:

the force due to magnetic fields lead to the cetripetal force, such that:

F = q×v×B = m×(v^2)/r

         q×B = m×v/r

then:

r = m×v/q×B

r = p/q×B

then, the kinetic energy of the proton:

K = 1/2×m×v^2 = p^2/(2×m)

q×B = \sqrt{2×m×K}/r

    r =  \sqrt{2×m×K}/(q×B)

      =  \sqrt{2×(1.67×10^-27)×(5.3×1.60×10^-13)}/(1.60×10^-19×0.39)

      = 0.85 m  

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Can you die if you bust a hemorrhoid?
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I think that you can die
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Write the nuclear reaction equation for the beta decay of Iodine-131
den301095 [7]

Answer:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

Explanation:

In a beta (minus) decay, a neutron in a nucleus turns into a proton, emitting a fast-moving electron (called beta particle) alongside with an antineutrino.

The general equation for a beta decay is:

^A_Z X \rightarrow _{Z+1}^AY+^0_{-1}e+ ^0_0\bar{\nu} (1)

where

X is the original nucleus

Y is the daughter nucleus

e is the electron

\bar{\nu} is the antineutrino

We observe that:

  • The mass number (A), which is the sum of protons and neutrons in the nucleus, remains the same in the decay
  • The atomic number (Z), which is the number of protons in the nucleus, increases by 1 unit

In this problem, the original nucles that we are considering is iodine-131, which is

_{53}^{131}I

where

Z = 53 (atomic number of iodine)

A = 131 (mass number)

Using the rule for the general equation (1), the dauther nucleus must have same mass number (131) and atomic number increased by 1 (54, which corresponds to Xenon, Xe), therefore the equation will be:

_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}

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