I think you forgot to give the options along with the question. I am answering the question based on my research and knowledge. Using safe research practices would be a very good <span>common-sense practice in a lab environment. I hope that this is the answer that has actually come to your desired help.</span>
Chemical reaction: C + O₂ → CO₂.
Law of conservation of mass <span>states that for any </span>system closed<span> to all transfers of </span>matter<span> and </span>energy<span>, the </span>mass<span> of the system must remain constant over time.
</span><span>In </span>chemical reactions<span>, the mass of the chemical components before the reaction (in this reaction carbon and oxygen) is equal to the mass of the components after the reaction (carbon dioxide).
</span>If we use one mole of substances, that:
mass of reactants is: 12 g (C) + 2·16 g (O) = 44 g.
mass of product is: 12 g + 32 g = 44 g.
We have to know the number of molecules present in 500 g of water.
The answer is: zero molecules present in 500g of water.
Water molecule is H₂O. In water molecule, nitrogen molecule can not be present. Molecular mass of water is 18 g. MOlecular mass of nitrogen molecule is 28 g.
500 g water contains 500/18 number of moles= 27.77 moles of water molecules which contains 27.77 X 6.023 X 10²³ number of water molecules.
There is no existence of N₂ molecule.
The chemical reaction is expressed as:
3Ba(NO3)2 + 2Na3PO4 = Ba3(PO4)2 + 6NaNO3
To determine the percent yield, we need to determine the theoretical yield of the reaction from the given amounts of the reactants. We do as follows:
0.3 mol 3Ba(NO3)2 ( 2 mol Na3PO4 / 3 mol Ba(NO3)2) = 0.2 mol Na3PO4
Therefore, the limiting reactant would be Ba(NO3)2 since it is consumed completely in the reaction.
Theoretical yield = 0.3 mol 3Ba(NO3)2 ( 1 mol Ba3(PO4)2 / 3 mol Ba(NO3)2) = 0.1 mol Ba3(PO4)2
Percent yield = actual yield / theoretical yield = 0.095 mol Ba3(PO4)2 / 0.1 mol Ba3(PO4)2 x 100 = 95%
Answer:
2.33*10^-15 s
Explanation:
We need to estimate the period of oscillation of an electron that bounced up/down due to the effects of a passing packet of red light. The period of oscillation is the wavelength of the red light divided by the speed of the red light. We know that:
V = f*λ
where V = speed of the red light = 3*10^8 m/s
f = frequency = 1/T where T is the period of oscillation in seconds (s)
λ = the wavelength of the red light = 0.7*10^-6 m
Thus:
V = λ/T
T = λ/V = (0.7*10^-6)/(3*10^8) = 2.33*10^-15 s
