Reduction takes place in cathode while oxidation takes place at the anode.
Given that the reaction 3MnO4- +24H + +5Fe→3Mn+2+5Fe+3+12H2O
Now that oxidation is termed as an increase in oxidation number or loss of electrons while reduction is a decrease in oxidation number and gain of electrons,
∴oxidation will be
Fe→Fe +3+3e-
reduction will
MnO4- +8H+ →Mn+2+4H2O
If oxidation takes place at anode then Anode: an oxidation reaction
Fe→Fe+3+3e- . Then the answer is
Fe(s)→Fe+3(aq)+3e-
3,500 miliseconds are in one second :)
Answer:
27 amu
Explanation:
The alpha particles is Helium nuclei.
Atomic mass is the sum of the neutrons and protons.
Helium have two protons and two neutrons thus its atomic mass is 4 amu.
₂He⁴
Sodium atom have 12 neutrons and 11 protons. Thus its mass number will be
23 amu.
When it combine with alpha particle it mass will be 27 amu.
23 amu + 4 amu = 27 amu.
Thus new sodium atom have 14 neutrons and 13 protons.
Answer:
The second option is correct
= Acid can dissolve many metals
Explanation:
Acid reacts with most metals to liberate hydrogen gas, during the process the metals dissolve in the acid
Answer:
Explanation:
Hello there!
In this case, for the given reactants side, we infer this is a double replacement reaction because all the cations and anions are switched around as a result of the chemical change, we infer that the products side include aluminum with nitrate and magnesium with sulfate as shown below:
However, we need to balance since unequal number of atoms are present at both sides, thus, we do that as shown below:
Thus, we make 6 Al atoms, 3 S atoms, 3 Mg atoms and 30 O atoms on each side in agreement with the law of conservation of mass.
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