Answer:
The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L
Explanation:
Given data:
Number of moles of HF = 6.62×10⁻³ mol
Volume of HF in litter at STP = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Standard temperature = 273 K
Standard pressure = 1 atm
Now we will put the values in formula.
1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K
V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 148.38×10⁻³ L
Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.
I believe it's better for it to be more abundant because it's better to have more then less. Take water as an example. Water is an important factor to our survival and if we didn't have enough of that we would be in trouble. Or if we needed food but there wasn't enough more people would be dying from starvation. It's better to have a little more than a little less.
Answer:
0.0123 moles
Explanation:
Concentration = Moles / Volume of solution
or you can rearrange the formula to get
Moles = concentration (moles/liter) x volume of solution (liter)
First convert your volume to L instead of mL. 35mL = 0.035L
moles = 0.350 moles/liter x 0.035 liter (liters cancel out)
moles = 0.0123
