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3 years ago

If the pH of a solution is 5.4 then the concentration of H+ ions is ___|_x10^-6

Chemistry

1 answer:

Svetllana [295]3 years ago

6 0

H is 4*10^6 M , OH is 2.5*10^-9 M

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the temperature is increased, the position of equilibrium moves to the left, and the yield of ammonia decreases.

igomit [66]

Answer:i don't rlly get the question but this is what i found on the internet :/

Explanation:

When the temperature is increased, the position of equilibrium moves in the endothermic direction to reduce the temperature. ... This means that as the temperature is increased, the position of equilibrium moves to the left, and the yield of ammonia decreases.

7 0

2 years ago

Which is the correct net ionic equation for the reaction of aqueous ammonia with nitric acid? Which is the correct net ionic equ

Svet_ta [14]

Answer:

The last option:

NH₃ (aq) + H⁺ (aq) → NH₄⁺ (aq)

Explanation:

1) Word equation

Aqueous ammonia + nitric acid → aqueous ammonium nitrate

2) Chemical (molecular) equation

NH₃ (aq) + HNO₃ (aq) → NH₄ NO₃

3) Ionization reactions

Write the dissociation of the soluble ionic compounds:

HNO₃ → H⁺ + NO₃⁻

NH₄ NO₃ → NH₄⁺ + NO₃⁻

4) Total ionic equation:

NH₃ (aq) + H⁺ (aq) + NO₃⁻ (aq) → NH₄⁺ (aq) + NO₃⁻ (aq)

5) Net ionic equation

You must cancel the spectator ions, which are those ions that are repeated in both reactant and product sides, i.e. NO₃⁻. They are name spectator because they do not participate (change) during the reaction.

NH₃ (aq) + H⁺ (aq) → NH₄⁺ (aq)

And that is the last choice of the list.

4 0

2 years ago

What is the hydrogen concentration of a solution with a pH of 2.1?

Black_prince [1.1K]

Answer:

8×10^(-3) mol/L

Explanation:

The formula for finding the hydrogen ion concentration is...

[H⁺] = 10^-ph

[H⁺] = 10^(-2.1)

[H⁺] = 0.00794...mol/L = 8×10^(-3) mol/L

The answer is to 1 significant digit because the pH has one decimal place.

5 0

3 years ago

Write packing efficiency of fcc ,BCC, SCC and formula also . ?

Minchanka [31]

❖ Packing Efficiency ❖

➪ The percentage of total space occupied by particles is called packing efficiency.

$\\ \qquad{\rule{200pt}{3pt}}$

$\bigstar \boxed{ \sf \: \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}$

❖ Packing efficiency of simple cubic structure (SCC).❖

$\rm \: {Let \: } \bf{r } \: \rm{ be \: the \: radius \: of \: a \: sphere }\: \\ \rm and \: \bf{a} \: \rm {be \: the \: edge \: of \: unit \: cell.} \\ \\ \; \bigstar \boxed{ \sf{Volume_{(sphere)} = \dfrac{4}{3} \pi r^3}} \bigstar$

❒ Since, simple cubic unit cell contain 1 atom (sphere). So, the total volume of sphere will be :

$: : \implies \sf \: 1 \times \dfrac{4}{3}\pi r^3 = \dfrac{4}{3}\pi r^3$

Volume of unit cell = a³

Volume of unit cell = (2r)³

Volume of unit cell = 8r³

❒ Now, we know that,❒

$\bigstar \boxed{ \sf \: \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}$

➪ Substituting the known values in the formula, we get the following results:

$: : \implies \rm \: {\dfrac{\dfrac{4}{3}\pi r^3}{8r^3} \times 100} \\ \\ : : \implies \dfrac{\pi}{6} \times 100 \\\\\ : : \implies \bf {52.4 \%}$

❒ Hence, the packing efficiency of simple cubic structure is 52.4%.

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➪ Packing efficiency of cubic close packing (SCC)/face centred cubic structure (FCC).

❒ Since, simple cubic unit cell contain 2 atom (sphere). So, the total volume of sphere will be:

$: : \implies \rm 4 \times \dfrac{4}{3}\pi r^3 = \dfrac{16}{3}\pi r^3$

Volume of unit cell = a³

Volume of unit cell = (2√2r)³

Volume of unit cell = 16√2r³

❒ Now, we know that,❒

$\bigstar \boxed{ \sf \: \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}$

➪Substituting the known values in the formula, we get the following results:

$: : \implies \rm {\dfrac{\dfrac{16}{3}\pi r^3}{16\sqrt{2}r^3} \times 100 }\\\\ \implies \rm \dfrac{\pi}{3\sqrt{2}} \times 100 \\\\\ \implies\bf52.4 \%$

❖ Hence, the packing efficiency of face centred cubic structure is 74%.

$\\ \qquad{\rule{200pt}{3pt}}$

❖ Packing efficiency of body cubic structure (BCC).

❒ Since, simple cubic unit cell contain 2 atom (sphere). So, the total volume of sphere will be:

$: : \implies \rm \: 2 \times \dfrac{4}{3}\pi r^3 = \dfrac{8}{3}\pi r^3$

Volume of unit cell = a³

Volume of unit cell = (4r/√3)³

Volume of unit cell = 64r³/3√3

❒ Now, we know that,❒

$\bigstar \boxed{ \sf \: \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}$

➪Substituting the known values in the formula, we get the following results:

$: : \implies \rm {\dfrac{\dfrac{8}{3}\pi r^3}{\dfrac{64r^3}{3\sqrt{3}}} \times 100} \\\\ \implies \dfrac{3\pi}{8} \times 100 \\\ \\ \bf \implies \: 68 \%$

❒ Hence, the packing efficiency of body centred cubic structure is 68%.

$\\ \qquad{\rule{200pt}{3pt}}$

6 0

2 years ago

DIMENSIONAL ANALYSIS PLSSSS convert 19 inches to feet(show work)

Anna [14]

19 in = 1.6 ft

You know that

12 in = 1 ft

If you divide both sides by 12 in, you get the conversion factor: 1 = 1 ft/12 in.

If you divide both sides by 1 ft, you get the conversion factor: 12 in/1 ft = 1.

Both are conversion factors because they both equal one and multiplying a measurement by one does not change its value.

You choose the conversion that gives you the correct dimensions for your answer. It must have the correct dimensions on top (in the numerator),

Thus, to convert 19 in to ft, you use the conversion factor with “ft” on the top.

∴ Length = 19 in × (1 ft/12 in) = 1.6 ft

6 0

2 years ago