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LenaWriter [7]
3 years ago
14

What are the measurements for standard temperature and pressure (stp)? kp?

Chemistry
1 answer:
Alex787 [66]3 years ago
8 0
Standard Temperature and Pressure (STP) are 273.15 K (Kelvin) and 101.3 KPa (kilopascals).

You can substitute 1 ATM (atmosphere) for the kilopascal measurement. It is discouraged to use 0°C for the temp equivalent since negative temperature numbers can't be used in gas equations..

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A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab
77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

  • By definition, pH = -log[H_3O^+].
  • NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq).
  • From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: [NaOH] = [OH^-].
  • Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: [OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}.
  • We also know that pOH = 14.00 - pH = -log[NaOH]. Take the antilog of both sides: 10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}.
  • Solve for the mass of NaOH: m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V.

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g

7 0
2 years ago
13. The attraction between water molecules and an Na+
a_sh-v [17]

Answer:

C) Polar......

:-)

Wish .It's help you.

8 0
2 years ago
Read 2 more answers
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