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Elza [17]
3 years ago
13

Which conclusion could be made from Ernest Rutherford's gold foil experiment?

Chemistry
2 answers:
solmaris [256]3 years ago
5 0

Answer:

Atoms are made up of mostly empty space.

Explanation:

nlexa [21]3 years ago
3 0
That there was a positive mass located somewhere in the atom which was called the nucleus. it also showed that most of the atom was empty space
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Two angles with measures (6x + 60) (90)<br> are supplementary. What is the value of x?
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Supplementary angles add up to 180, so
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Why is each year's vaccine different?
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Indicate the number of significant figures in the measured number 0.0020 <br> A. 4<br> B. 5<br> C. 2
Sergio [31]

<u>Answer:</u>

The correct answer option is C. 2.

<u>Explanation:</u>

We are given the number '0.0020' and we are to indicate the number of significant figures in the given measured number.

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6 0
3 years ago
How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
3 years ago
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