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olganol [36]
3 years ago
7

I need help with number 3

Mathematics
2 answers:
yan [13]3 years ago
7 0
First check whether the point (-6,8) is the solution to any of the equations. To check, just plug in the x and y values of the points into the equation and see if they give you a true statement. 
5(-6)+3(8)=-6
-30+24=-6
-6=-6
That's a true statement so the point is the solution to the first equation.
2(-6)+(8)=-4
-12+8=-4
-4=-4
It is a true statement so the point is a solution for both equations
There are no other solution because lines can only intersect in one or infinite points, but that is only if they are the same lines, which is not true in this circumstance.
A. It is the only solution to the set. 
Hope this helps.
Arte-miy333 [17]3 years ago
5 0
D because it is i know it is
          
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<h2>Answer:</h2>

<em><u>(a). 110</u></em>

<em><u>(b). 95 </u></em>

<em><u>(c). 2</u></em>

<h2>Step-by-step explanation:</h2>

In the question,

Number of students who played Basketball = 99

Number of students who played Volleyball = 9

Number of students who played Soccer = 10

Number of students who played Basketball and Soccer only = 1

Number of students who played Volleyball and Soccer only = 2

Number of students who played Basketball and Volleyball only = 1

Number of students who played Basketball, Volleyball and Soccer only = 2

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We can see from the <u>Venn diagram</u> shown below,

Number of students who played only Basketball = 99 - (1 + 2 + 1) = 95

Number of students who played only Volleyball = 9 - (1 + 2 + 2) = 4

Number of students who played only Soccer = 10 - (1 + 2 + 2) = 5

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Number of students who played atleast one of three sports = Sum of all the sections in the Venn Diagram

= (95 + 1 + 2 + 1) + (4 + 2) + 5 = 110

(b).

Students who played Basketball only = 95

(c).

Number of students who play Volleyball and Soccer but not Basketball = 2

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