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Rufina [12.5K]
2 years ago
11

A temperature of 200°F is equivalent to approximately A. 840°C. B. 93.3°C. C. 232°C. D. 37.8°C

Physics
2 answers:
Eduardwww [97]2 years ago
5 0
The equivalent of 200F is 93.3C

timofeeve [1]2 years ago
5 0
The answer is B. 93.3 C
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2 years ago
A 72.0 kg stuntman jumps from a moving car to a 2.50 kg skateboard at rest. If the velocity of the car is 15.0 m/s to the east w
yawa3891 [41]

Answer:

B 14.5 m/s to the east

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, if the system is isolated, the total momentum of the system must be conserved.

Here the total momentum before the stuntman reaches the skateboard is:

p_i = Mv

where

M = 72.0 kg is the mass of the stuntman

v = 15.0 m/s is his initial velocity (to the east)

The total momentum after the stuntmen reaches the skateboard is:

p_f = (M+m)v'

where

m = 2.50 kg is the mass of the skateboard

v' is the final velocity of the stuntman and the skateboard

Since momentum must be conserved, we have

p_i = p_f\\Mv=(M+m)v'

And solvign for v',

v'=\frac{Mv}{M+m}=\frac{(72.0)(15.0)}{(72.0+2.50)}=14.5 m/s

And since the sign is the same as v, the direction is the same (to the east).

7 0
3 years ago
A 38-kg canoe breaks free from its dock and floats downriver at a speed of 2.2 m/s. What is the momentum of the canoe? 48.0 m/s
Brut [27]
Momentum of a body is calculated by multiplying the mass of a moving body with its velocity. When a body is at rest it has zero momentum since the velocity is also zero.
In this case the momentum of the canoe will be;
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Therefore, the correct answer is 83.6 kg m/s
3 0
3 years ago
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructi
pochemuha

Answer:

Chemical

Explanation:

6 0
2 years ago
A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats
MAVERICK [17]

Answer:

The answer is below

Explanation:

The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:

V² = 56² + 126²

V² = 19012

V = 137.9 m/s

7 0
2 years ago
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