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netineya [11]
3 years ago
6

a baseball pitcher throws a fastball at 42 meters per second. if the batter is 18 meters from the pitcher, approximately how muc

h time does it take for the ball to reach the batter?
Physics
2 answers:
lapo4ka [179]3 years ago
6 0
T=D/v = 18/42 = 43 seconds
LiRa [457]3 years ago
4 0
T = distance div time = 18/42 = 3/7 seconds = 0.4 seconds

less than half of a second

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Given the data in the question;

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v₂ = 0.856 √(14W₁  / W₁ )

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v₂  = 0.856 √( 14(1)

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