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Lunna [17]
4 years ago
14

1/2y=1 in standard form

Mathematics
1 answer:
velikii [3]4 years ago
6 0

Answer:

1 = 2y(1)

1= 2y

y = 1

Step-by-step explanation:

I hope to help

Greetings from Peru

I speak Spanish not English

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What is the range of the graph below?<br>​
torisob [31]

Answer:

B) -4 < y

Step-by-step explanation:

The lowest point on the y axis of the graph is -4 and everything else is higher

6 0
3 years ago
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
3 years ago
20 points!!! first answer gets brainliast. Don't need too much explanation thank you!​
KengaRu [80]

Answer:

The answer to your question is below

Step-by-step explanation:

2. \sqrt{-128}                Just find the prime factors of 128 and simplify

   \sqrt{-2^{7}} = \sqrt{-2^{6} 2} = 2^{3}i \sqrt{2}

   8i\sqrt{2}

3.- \sqrt{-9} + \sqrt{-16}     Get the square roots and simplify

     3i + 4i

     7i

4.- None of the choices is equal to one, because the exponents are pair.

5.- 1/3x² + 10 = 7

    1/3x² = 7 - 10

    1/3x² = -3

         x² = -3(3)

         x² = -9

         x = ±3i

8 0
4 years ago
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