There would be no mass or weight and he would float away
<h3><u>Answer;</u></h3>
Frequency
<h3><u>Explanation;</u></h3>
- <em><u>Waves are disturbances that travel through a material medium. There are several characteristics of waves, which includes; wavelength, frequency, period and amplitude. </u></em>
- Amplitude is the maximum displacement of wave particles, or simply the height of the wave, measured in meters.
- Wavelength is the distance between adjacent crests or troughs in a transverse wave or between two successive rarefaction or compressions in a longitudinal wave, measured in meters.
- Period is the time it takes for one complete wave to pass a given point, measured in seconds.
- <em><u>Frequency is the number of complete waves or cycles that pass a point in one second, measured is inverse seconds, or Hertz (Hz).</u></em>
Explanation:
Lasers produce a narrow beam of light in which all of the light waves have very similar wavelengths. The laser's light waves travel together with their peaks all lined up, or in phase. This is why laser beams are very narrow, very bright, and can be focused into a very tiny spot.
Answer:
Pressure, P = 32666.66 Pa
Explanation:
It is given that,
Surface area of foot of Bimaba is 150 cm² or 0.015 m².
Her weight is 50 kg
We need to find the pressure does she exert on the ground, as she stands on her one foot. The force acting per unit area is called pressure. It can be given by :

So, the pressure is 32666.66 Pa.
The speed of the block when the compression is 15 cm is 9.85 m/s.
The given parameters;
- <em>mass of the block, m = 2.4 kg</em>
- <em>height of the block, h = 5 m</em>
- <em>compression of the spring, x = 25 cm = 0.25 m</em>
The spring constant is calculated as follows;

The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;

Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.
Learn more here:brainly.com/question/14289286