The magnetic flux that passes through one turn of a 26-turn coil of wire changes to 4.5 Wb from 12.0 Wb in a time of 0.034 s. Th
1 answer:
Answer:
The resistance of the wire is 1.47 ohms
Explanation:
Electromagnetic induction is a physical phenomenon that consists on generate electric current changing magnetic flux. The magnitude of the electromotive force (emf) generated by the change on magnetic flux is given by Faraday-Lenz law:
with N the turns of the coil, and phi_{B} the magnetic flux.
So, in our case because the magnetic flux changes from 12.0 Wb to 4.5 Wb on 0.034 seconds.
The electromotive force acts as voltage source for the coil, so we can use Ohm's law:
with I the current, R the resistance and V the voltage (the emf), solving for R
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Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.